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ziro4ka [17]
3 years ago
13

EFG is isosceles as shown in the diagram. Find the measure of angle ∠GED. (no links, and i will mark brainliest.)

Mathematics
1 answer:
Aleks [24]3 years ago
3 0

Answer:

m<GED = 126°

Step-by-step explanation:

The base angles of an isosceles are equal.

This implies that:

m<FEG = m<F

Thus:

m<F = ½(180° - 72°)

m<F = ½(108°)

m<F = 54°

Based on the exterior angle theorem, we have the following equation:

m<F + m<FGE = m<GED

Substitute

54° + 72° = m<GED

126° = m<GED

m<GED = 126°

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In ΔJKL, \overline{JL} JL is extended through point L to point M, m∠JKL = (2x+14)^{\circ}(2x+14) ∘ , m∠LJK = (3x+15)^{\circ}(3x+
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Check attachment for solution.

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