If the length is x feet, the width is (x + 5) feet. Formulate an equation:
2x + 2 (x + 5) = 54
2x + 2x + 10 = 54
4x = 54 - 10
4x = 44
x = 44 : 4
x = 11
Answer: the length of the garden is 11 feet.
18,36, and 54. These are the common multiple of 6 and 9
9514 1404 393
Answer:
∠E = 48°
Step-by-step explanation:
The sum of angles in a quadrilateral is 360°.
(5x +3)° +88° +(10x +7)° +127° = 360°
15x = 135 . . . . divide by °; subtract 225
x = 9 . . . . . . . . divide by 15
Then angle E is ...
∠E = (5·9 +3)°
∠E = 48°
Check the picture below.
let's recall that in a Kite, the diagonals meet at 90° angles, therefore, we know the height of each of those 4 triangles, is 2.5 and 6, now, since the pair of triangles above are 45-45-90 triangles, we can use the 45-45-90 rule, as you see there, so, if the height is 2.5, then the base is also 2.5.
so, we really have 2 pair of triangles whose base is 2.5 and height of 2.5, and another pair of triangles whose base is 2.5 and height is 6, let's add their areas.
![\bf \stackrel{\textit{area of 2 triangles above}}{2\left[\cfrac{1}{2}(2.5)(2.5) \right]}~~+~~\stackrel{\textit{area of 2 triangles below}}{2\left[ \cfrac{1}{2}(2.5)(6) \right]}\implies 6.25+15\implies 21.25](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Barea%20of%202%20triangles%20above%7D%7D%7B2%5Cleft%5B%5Ccfrac%7B1%7D%7B2%7D%282.5%29%282.5%29%20%5Cright%5D%7D~~%2B~~%5Cstackrel%7B%5Ctextit%7Barea%20of%202%20triangles%20below%7D%7D%7B2%5Cleft%5B%20%5Ccfrac%7B1%7D%7B2%7D%282.5%29%286%29%20%5Cright%5D%7D%5Cimplies%206.25%2B15%5Cimplies%2021.25)