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Ede4ka [16]
3 years ago
13

Mr. Bruce has some clay with a mass of 24 kilograms. If he puts the same amount of clay into 6 bags, how many grams of clay are

in each bag? I NEED THE EXPLANATION
Mathematics
2 answers:
fomenos3 years ago
6 0
So you do 24 kg divided by six which is 4 so there is 4kg of clay in each bag
patriot [66]3 years ago
3 0

Answer:

4000grams in each bag

Step-by-step explanation:

Assume he put x amount of clay into each bag, he then put 6x into 6 bags.(since the question didn’t mention, I assume he put every clay he has into the bags)

6x=24kg

x=4kg

Since the question is asking for grams not kilograms:

4kg=4000g

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What is the 6th term of the geometric sequence where a1 = -4096 and a4 = 64?
Akimi4 [234]
\bf \begin{array}{llccll}
term&value\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
a_1&-4096\\
a_2&-4096r\\
a_3&-4096rr\\
a_4&-4096rrr\\
&-4096r^3\\
&64
\end{array}\implies -4096r^3=64
\\\\\\
r^3=\cfrac{64}{-4096}\implies r^3=-\cfrac{1}{64}\implies r=\sqrt[3]{-\cfrac{1}{64}}
\\\\\\
r=\cfrac{\sqrt[3]{-1}}{\sqrt[3]{64}}\implies \boxed{r=\cfrac{-1}{4}}\\\\
-------------------------------

\bf n^{th}\textit{ term of a geometric sequence}\\\\
a_n=a_1\cdot r^{n-1}\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
r=-\frac{1}{4}\\
a_1=-4096\\
n=6
\end{cases}
\\\\\\
a_6=-4096\left( -\frac{1}{4} \right)^{6-1}\implies a_6=-4^6\left( -\frac{1}{4} \right)^5
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3 years ago
Read 2 more answers
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Answer:

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Step-by-step explanation:

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4 years ago
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Answer:

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Step-by-step explanation:

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