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AveGali [126]
3 years ago
6

Write the following percents as both fractions and decimals.

Mathematics
1 answer:
wolverine [178]3 years ago
4 0

Answer:

1/4, 0.25

13/40, 0.325

1/25, 0.04

3/4, 0.75

13/200, 0.065

1 1/4, 1.25

1/8, 0.125

1/500, 0.002

3/400, 0.0075

107/100, 1.07

21/10, 2.10

9/40, 0.225

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Which statement is true about "f(x)"
Kazeer [188]

ANSWER

The graph of f(x) is horizontally stretched.

EXPLANATION

The given function is

f(x) =  -  \frac{2}{3}  |x + 4|  - 6

The vertex of this function is (-4,-6)

The factor ⅔ strectches the graph horizontally in the graph of f(x) opens wider than the parent function

y=|x|

The negative factor will make the graph open downwards. It is a reflection in the x-axis.

The domain of the graph is all real numbers.

3 0
3 years ago
Read 2 more answers
To investigate whether or not people tend to marry spouses of similar ages or whether husbands tend to be older than their wives
ira [324]

Answer:

See explanation below

Explanation:

1) Option C is correct.

The average difference in husband and wife marriage ages in Cumberland County; μd

2) Option D is correct.

Null: The average difference in marriage ages in Cumberland County is 0.

Alt: The average difference in marriage ages is greater than 0.

3) Option A is correct

Null: μd = 0

Alt: μd > 0

4) Given:

n = 24

d' = 1.875

Sd = 4.812

Find test statistic:

t = \frac{d'}{Sd/\sqrt{n}}

= \frac{1.875}{4.812/\sqrt{24}}

t = 1.909

Degree of freedom, df = n - 1 = 24 - 1 = 23

Pvalue = (t_2_3 > 1.909) = 0.0344

Pvalue = 0.0344

Significance level = 0.05

5) Since p value is less than significance level, reject null hypothesis H0

Hence, there is strong evidence that, on average, husbands are older than their wives in Cumberland County

5 0
3 years ago
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stiv31 [10]
X = -8-y/4 hope this helps
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