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olga nikolaevna [1]
3 years ago
13

WILL MAKE BRAINLIST!!!!!!

Mathematics
1 answer:
bixtya [17]3 years ago
4 0

Answer:

To do this, subtract 6 from both sides. − 3_x_ + 6 − 6 > 12 − 6. −3_x_ > 6. Now divide both sides of the inequality by −3. Since you're dividing by a negative number, you need to flip the inequality sign.

Step-by-step explanation:

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Find the missing value. If not whole number, leave in simplest radical form. PLEASE HELP!!
otez555 [7]

Answer:

I think the answer is:

-Y = 7

-Z = 10.63

-X = 9.22

Step-by-step explanation:

Hope this helps!

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6 0
3 years ago
6/6=42/_<br>Fill the blank space with the answer ​
artcher [175]

Answer:

42

Step-by-step explanation:

6/6 = 1

42/42 = 1

8 0
3 years ago
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The numbers 0,1/2, -53 and 0.433 all belong to which category ?
kirill [66]
0, 1/2, -53, and 0.433 all belong in rational category
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4 years ago
Is 210879 divisible by 3
Setler79 [48]

Answer:

Yes

Step-by-step explanation:

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7 0
3 years ago
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determine the slope of the tangent to the curve at the point y=(3x)(sinx) at the point with x-coordinate pi/2 ​
damaskus [11]

Answer:

Step-by-step explanation:

The slope of the tangent to a curve is the derivative of the curve. We need to find the derivative of the function and then evaluate the derivative at that given x value. The derivative is found using the product rule:

y'=f(x)g'(x)+f'(x)g(x)

Let's call 3x our f(x) and sin(x) our g(x). Filling in the formula for the derivative using the product rule looks like this:

y'=3x(cosx)+3sinx

That gives us the derivative, which is the slope formula that can be used at ANY x value anywhere on the curve to find the slope of the line tangent to the curve at that x value. If we want to find the slope of the tangent line to the curve at x = pi/2, we evaluate the slope formula at x = pi/2 (remember that y' is the same exact thing as the slope):

y'(slope)=3(\frac{\pi}{2})(cos\frac{\pi}{2})+3(sin\frac{\pi}{2})

From the unit circle (or experience, since you're in advaced math), we know that the cosine of pi/2 is 0 and that the sin of pi/2 = 1:

y'(slope)=3(\frac{\pi}{2})(0)+3(1) simplifies to

y' (slope) = 3

That means that the slope of the line tangent to the curve at the point x = pi/2 is 3.

8 0
4 years ago
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