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3 years ago

WILL MAKE BRAINLIST!!!!!!

Mathematics

1 answer:

bixtya [17]3 years ago

4 0

Answer:

To do this, subtract 6 from both sides. − 3_x_ + 6 − 6 > 12 − 6. −3_x_ > 6. Now divide both sides of the inequality by −3. Since you're dividing by a negative number, you need to flip the inequality sign.

Step-by-step explanation:

You might be interested in

How do I find x and y using what is in the equation

Tatiana [17]

y is part of a right angle on line AB

a right angle = 90 degrees

90-47 = 43 degrees

y = 43 degrees

a straight line = 180 degrees

180-47 = 133 degrees

x = 133 degrees

5 0

3 years ago

The isosceles trapezoid is part of an isosceles triangle with a 34 degree vertex angle. What is the measure of an acute base ang

Sonja [21]

For the answer to the question above asking what is the measure of an acute base angle of the trapezoid?
n acute base angle of the trapezoid would be the same as the triangle.

subtract 34º from 180º, then divide by 2. 

(180 - 34)/2 = 73º
I hope my answer helped you.

4 0

3 years ago

Suppose you want to build a small walkway around your garden so that there is someplace to walk around and work on your vegetabl

wolverine [178]

Answer:

Approximately 3.5 feet - Option B

Step-by-step explanation:

Imagine that you have this walkway around the garden, with dimensions 30 by 20 feet. This walkway has a difference of x feet between it's length, and say the dimension 30 feet. In fact it has a difference of x along both dimensions - on either ends. Therefore, the increases length and width should be 30 + 2x, and 20 + 2x, which is with respect to an increases area of 1,000 square feet.

( 30 + 2x ) $*$ ( 20 + 2x ) = 1000 - Expand "( 30 + 2x ) $*$ ( 20 + 2x )"

600 + 100x + 4 $x^2$ = 1000 - Subtract 1000 on either side, making on side = 0

4 $x^2$ + 100x - 400 = 0 - Take the "quadratic equation formula"

( Quadratic Equation is as follows ) - $x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ ,

$x=\frac{-100+\sqrt{100^2-4\cdot \:4\left(-400\right)}}{2\cdot \:4}:\quad \frac{5\left(\sqrt{41}-5\right)}{2}$ ,

$x=\frac{-100-\sqrt{100^2-4\cdot \:4\left(-400\right)}}{2\cdot \:4}:\quad -\frac{5\left(5+\sqrt{41}\right)}{2}$

There can't be a negative width of the walkway, hence our solution should be ( in exact terms ) $\frac{5\left(\sqrt{41}-5\right)}{2}$ . The approximated value however is 3.5081...or approximately 3.5 feet.

4 0

3 years ago

Today only, a desk is being sold at a 35% discount. The sale price is $611.

vaieri [72.5K]

The price was $824.85 before the discount (yesterday)

5 0

4 years ago

14. Find the solution of the initial value problem y′′ + y = F(t), y(0) = 0, y′(0) = 0, where F(t) = ⎧⎪⎨⎪⎩ At, 0≤ t ≤ ????, A(2?

Vinvika [58]

Yxgxgggffggyygfccccgyu

3 0

3 years ago