The library made a table to track the number of fiction and nonfiction books checked out for 6 days.

Need help if I fail this class again

jolli1 [7]

Answer:

7. f(x) = 4x+1

8. g(x) = 3^x

9. g(x)

Step-by-step explanation:

The graph of f(x) is a straight line that crosses the y-axis at y=1, and passes through another grid intersection at (1, 5). This grid intersection is 1 unit right and 4 units up from the y-intercept. This means the slope of the line is ...

slope = rise/run = 4/1 = 4

In slope-intercept form, the function f(x) is ...

f(x) = mx +b . . . . . . where the slope is m and the y-intercept is b

f(x) = 4x +1

__

The horizontal asymptote and the rapid rate of rise of g(x) tells us this is an exponential function. The generic exponential function is of the form ...

g(x) = a·b^x

The value of 'a' is the y-intercept, which is the same as for f(x). That is, a=1. The value when x=1 is ...

g(1) = a·b^1 = ab

We observe from the graph that g(1) is 3, so ...

g(1) = 3 = ab = 1b ⇒ b = 3

Using the values of 'a' and 'b', we have ...

g(x) = 3^x

__

We observe that g(x) is already greater than f(x) for x > 2, so g(x) will be greater in the long run.

(In the long run, an exponential function will exceed any polynomial function.)

3 0

2 years ago

Please help me with the question below (also please explain).

devlian [24]

To find the surface area of the given figure identify all the faces on the figure, calculate the area of each face and then sum the areas:

Measures in red

Number of faces in green, total faces 9

Area of a triangle:

$A=\frac{1}{2}bh$

Area of a rectangle:

$A=bh$

Area of faces 1 and 2(rectangles):

$\begin{gathered} A_1=A_2=20in*11in \\ A_1=A_2=220in^2 \end{gathered}$

Area of faces 3 and 4 (triangles):

$\begin{gathered} A_3=A_4=\frac{1}{2}(12in)(9in) \\ \\ A_3=A_4=54in^2 \end{gathered}$

Area of faces 5 and 6 (rectangles):

$\begin{gathered} A_5=A_6=12in*5in \\ A_5=A_6=60in^2 \end{gathered}$

Area of faces 7 and 8 (rectangles):

$\begin{gathered} A_7=A_8=20in*5in \\ A_7=A_8=100in^2 \end{gathered}$

Are of face 9 (rectangle):

$\begin{gathered} A_9=20in*12in \\ A_9=240in^2 \end{gathered}$

Total surface area:

$\begin{gathered} SA=A_1+A_2+A_3+A_4+A_5+A_6+A_7+A_8+A_9 \\ \\ SA=220in^2+220in^2+54in^2+54in^2+60in^2+60in^2+100in^2+100in^2+240in^2 \\ \\ SA=1108in^2 \end{gathered}$ <h2>Then, the surface area of the given figure is 1108 square inches</h2>

4 0

1 year ago

A series RLC circuit contains an inductor with a value of 200 millihenries and a capacitor with a value of 0.1 microfarad. What

vaieri [72.5K]

Answer:

1125.4 Hz

Step-by-step explanation:

The resonant frequency is the frequency at with the inductive reactance is equal to the capacitive reactance. It is given by the relation ...

$f=\dfrac{1}{2\pi\sqrt{LC}}$