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Oksana_A [137]
3 years ago
7

The library made a table to track the number of fiction and nonfiction books checked out for 6 days.

Mathematics
2 answers:
VikaD [51]3 years ago
8 0
Can you put a picture of the box?
Karolina [17]3 years ago
3 0
Can u attach a picture
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The length of line segment AD is 6.8 cm. The length of line segment AB is 3 cm. The length of line segment BC is 1.6 cm. Find th
saw5 [17]

Answer:

9.6

Step-by-step explanation:

This is a four side figure which is most likely to be a trapezium.So AD is the hypotenuse,AB is side (a),BC is the height and CD is side (b).

6 0
2 years ago
What is the equation of a circle with center (-7,4) and radius 8?
enot [183]
The answer to this question is 
B. (x+7)²+(y-4)²=64 

I hope this helps!!!!!!!

7 0
3 years ago
Read 2 more answers
Which of the following are operations in the algebra of sets?
postnew [5]

Answer:

Union and Intersection

Step-by-step explanation:

We know that the algebra of sets define the properties and laws of the sets.

The basic operations of sets are,

Union, Intersection, Complement of a set and Equality of sets.

Since, the operations addition, subtraction, multiplication and division are the basic arithmetic operations of numbers.

i.e. they are not in the algebra of sets.

So, we get that out of the given options, the operations in algebra of sets are Union and Intersection.

7 0
3 years ago
The model represents an equation.
madreJ [45]

Answer:

9/5

Step-by-step explanation:

solve the original equation for x

-4× + 3 = 1x +(-6)

-1x

-5x + 3 = -6

-3

-5x = -9

/-5

x = 9/5

CHECK

-4(9/5) + 3 = 1(9/5) +(-6)

-21/5 = -21/5

8 0
3 years ago
(5+2 i)(4-3i) - (5-2yi)(4-3i) in a + bi form, where y is a real number.
ElenaW [278]
<span>(5+2 i)(4-3i) - (5-2yi)(4-3i)

Factorize out (4 -3i)

(4 -3i)( (5 +2i) - (5 -2yi) )

=  </span><span><span>(4 -3i)(5 +2i - 5 + 2yi)</span>

=  </span><span><span>(4 -3i)(5 - 5 + 2i + 2yi)</span>

= (4 -3i)(2i + 2yi)

= (4 - 3i)(2 + 2y)i.    Let's multiply the first two.
</span>
(4 - 3i)(2 + 2y) = 2*(4 -3i) + 2y*(4 - 3i)           
                      =  8 - 6i + 8y - 6yi
                      =  8 + 8y - 6i - 6yi

(4 - 3i)(2 + 2y)i = (8 + 8y - 6i - 6yi)i                Note: i² = -1
                       =  8i  + 8yi - 6i² - 6yi²
                       =  8i  +  8yi - 6(-1) - 6y(-1)  
                       =  8i  +  8yi  + 6 + 6y
                       =  6 + 6y + 8i + 8yi
                       =  (6 + 6y) + (8 + 8y)i    In the form a + bi
5 0
3 years ago
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