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kumpel [21]
3 years ago
10

How many grams of CaCl2 (molar mass =111g/mol) are needed to prepare 100.mL of 0.100MCl−(aq) ions?

Advanced Placement (AP)
2 answers:
MA_775_DIABLO [31]3 years ago
3 0

Answer:

hbvf

Explanation:

Setler [38]3 years ago
3 0

Answer: 1.11 grams

Explanation:

1.11g/111 M = .01

100mL = .1 L

.01/.1 = .1

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