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Nookie1986 [14]
3 years ago
11

What is the acceleration of an object if the object has an initial speed of 230 m/s and speeds up to 650 m/s. The time it takes

for this to happen is 30 seconds.
Physics
1 answer:
enot [183]3 years ago
8 0

Answer:

a= v -u\ t

650- 230\ 30

= 420\30

=14 m\s²

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Three thermometers are in the same water bath. After thermal equilibrium is established, it is found that the Celsius thermomete
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Answer:

OPTION A, Kelvin Thermometer is Incorrect

Explanation:

Now, if you consider best two out of three results, then celsius and Fahrenheit thermometers read the same value, meaning both are right.

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3 years ago
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Answer:

Explanation:

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A plane designed for vertical takeoff has a mass of 8.0 × 10³ kg. Find the net work done by all forces on the plane as it accele
artcher [175]

Answer:

<em>the net work done after starting from rest is =  2.4 × 10⁵ J</em>

Explanation:

Work: Work can be defined as the product of force and distance. The fundamental unit of work is Joules (J),  The unit of Energy is Joules (J), as such Energy and work are interchangeable during calculation, This is illustrated below

E = W = 1/2mv².......................... Equation 1

Where m = mass of the plane, v = velocity of the plane, E = Energy, W = work done.

v² = u² + 2as ................................. Equation 2.

Where v = final velocity of the plane, u = initial velocity of the plane, a = acceleration of the plane, distance of the plane.

<em>Given: a = 1.0 m/s², s = 30 m, u = 0 m/s (at rest)</em>

<em>Substituting these values into equation 2</em>

<em>v² = 0² +2×1×30</em>

<em>v² = 60</em>

<em>v = √60</em>

<em>v = 7.75 m/s</em>

Also given: m = 8.0 × 10³ kg, and v = 7.75 m/s

<em>Substituting these values into equation 1,</em>

<em>W = 1/2(8.0×10³)(7.75)²</em>

<em>W = (4.0×10³)(60)</em>

W = 240 × 10³ J

<em>W = 2.4 × 10⁵ J</em>

<em>Therefore the net work done after starting from rest is =  2.4 × 10⁵ J</em>

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