Can someone help me with this? all of the info is in the pic

Six plus five times a number is more than the

amm1812

Answer:

x > 0.5

Step-by-step explanation:

Let the number be x.

6 + 5x > x + 8

4x > 2

x > 0.5

This is a question on inequalities. If you wish to venture further into it/understand this topic better, you may want to follow my Instagram account (learntionary), where I post some of my own notes on certain topics and also some tips that may be useful to you :)

8 0

3 years ago

Which of the following are solutions to -2.7 + x = -3.5?

algol [13]

Answer:

-3.5+27

Step-by-step explanation:

-2.7+x=-3.5

x=-3.5-(-2.5)

x=-3.5+2.5

x=2.0

4 0

3 years ago

Given a radius of 9 inches, estimate the length of arc s to the nearest hundredth.

malfutka [58]

The question is incomplete, here is the complete question:

Given a radius of 9 inches intercepted by the central angle 60°. Estimate the length of arc 'S' to the nearest hundredth.

Answer: The arc length of the circle is 9.42 inches

Step-by-step explanation:

To calculate the length of the arc, we use the formula:

$S=2\pi r(\frac{\theta}{360})$

where,

S = arc length = ?

r = radius of the circle = 9 inches

$\theta$ = central angle = 60°

Putting values in above equation, we get:

$S=2\times 3.14\times 9\times (\frac{60}{360})\\\\S=9.42in$

Hence, the arc length of the circle is 9.42 inches

6 0

3 years ago

Read 2 more answers

How to find the perimeter of the triangle

Sliva [168]

Answer:

A. 26.2

Step-by-step explanation:

To find the perimeter of the triangle, you have to find the distances of all three lines and add them up.

Line AB

Let's start off by finding the distance of line AB.

We will use the formula, $d = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ .

Point A is (-2,5) and Point B is (4,-3).

To substitute the values, it will get to $d = \sqrt{(4--2)^{2}+(-3-5)^{2}}$ which in other words is $d = \sqrt{(4+2)^{2}+(-3-5)^{2}}$ .

Now we have to solve the parenthesis to get $d = \sqrt{(6)^{2}+(-8)^{2}}$ .

Now we have to solve the exponents which would get to $d = \sqrt{36+64}$ .

Now we have to simplify the square root to $d = \sqrt{100}$ . In other words, that is $d = 10$ .

Line AB = 10

Line BC

Now let's find the distance of line BC.

We will use the same formula, $d = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ .

Point B is (4,-3) and Point C is (0,-6).

To substitute the values, it will get to $d = \sqrt{(0-4)^{2}+(-6--3)^{2}}$ which in other words is $d = \sqrt{(0-4)^{2}+(-6+3)^{2}}$ .

Now we have to solve the parentheses to get $d = \sqrt{(-4)^{2}+(-3)^{2}}$ .

Now we have to solve the exponents which would get to $d = \sqrt{16+9}$ .

Now we have to simplify the square root to $d = \sqrt{25}$ . In other words, that is $d = 5$ .

Line BC = 5.

Line AC

Now let's fine the distance of line AC.

We will use the same formula, $d = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ .

Point A is (-2,5) and Point C is (0,-6).

To substitute the values, it will get to $d = \sqrt{(0--2)^{2}+(-6-5)^{2}}$ which in other words is $d = \sqrt{(0+2)^{2}+(-6-5)^{2}}$ .

Now we have to solve the parentheses to get $d = \sqrt{(2)^{2}+(-11)^{2}}$ .

Now we have to solve the exponents which would get to $d = \sqrt{4+121}$ .

Now we have to simplify the square root to $d = \sqrt{125}$ . In other words, that is $d = 5\sqrt{5}$ . To round that, $d = 11.2$ .

Line AC = 11.2.

Perimeter of Triangle ABC

Perimeter of Triangle ABC = Line AB + Line BC + Line AC.

Perimeter of Triangle ABC = 10 + 5 + 11.2

Perimeter of Triangle ABC = 26.2

Hope this helped! If not, please let me know <3

3 0

3 years ago

Write an equation in point-slope form of the line that passes through the points (-5,-4) and (7,-5).

Anettt [7]

Step 1 :

Given point(x1x1, y1y1) = (5, -4) and slope(m) = -2

Answer :

-2x - y + 6

4 0

3 years ago