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qwelly [4]
4 years ago
7

HURRY PLEASEEE Evaluate the expression when y = 4 Y/2-8=

Mathematics
1 answer:
dmitriy555 [2]4 years ago
5 0
- 1 1/2 (Negative one and one half
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Solve for X $1200 is 10% of X
iogann1982 [59]

Answer:

X = 12000

Step-by-step explanation:

1200 is 10% of X

Writing in equation form, we get,

1200 = \frac{10}{100}  * X\\X = \frac{1200*100}{10}\\X = 12000

6 0
3 years ago
Find y when x = 12, if y = 2 when x = 5
AleksAgata [21]
Y = kx
k = y/x
k = 2/12
k = 1/6

so when x = 12
y = kx
y = 1/6(5)
y = 5/6

answer
when x = 5  y = 5/6
7 0
3 years ago
A parcel delivery service will deliver a package only if the length plus girth (distance around) does not exceed 84 in. What are
Lesechka [4]

Answer:

a) \frac{28}{\pi} in

b) 28 in

c) 784 in²

Step-by-step explanation:

Let the length be 'L'

and the radius be 'r'

Thus, according to the question

L + 2πr = 84 in

L = 84 - 2πr   ............(1)

Volume of the cylinder, V = πr²L

substituting the value of L from 1, we get

V =  πr²(84 - 2πr)

or

V = 84πr² - 2π²r³

for points of maxima, differentiating the above equation and equating it to zero

\frac{dV}{dr}=\frac{d(84\pi r^2-2\pi^2 r^3))}{dr}

or

2(84)πr - 3(2)π²r² = 0

or

2πr(84 - 3πr) = 0

or

r = 0    and    84 - 3πr = 0

or

⇒ 3πr = 84

or

⇒ r = \frac{28}{\pi} in

since, the radius cannot be zero therefore, r = 0 is neglected

Therefore,

a) The radius of the largest cylindrical package = \frac{28}{\pi} in

b) from  (2)

L = 84 - 2πr

or

⇒ L = 84 - 2\pi\times\frac{28}{\pi}

or

⇒ L = 84 - 56 = 28 in

The length of the largest cylindrical package = 28 in

c ) The volume of the largest cylindrical package ,V = πr²L

= \pi\times\frac{28}{\pi}\times28

= 784 in²

7 0
3 years ago
I don't understand 1 and 2
Trava [24]
1. addition
2. subtraction
8 0
4 years ago
Find the distance between the points (2,-1) and (-1,-4). Round your answer to the nearest hundredth.
romanna [79]

Answer:

4.24

Step-by-step explanation:

8 0
3 years ago
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