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Romashka [77]
3 years ago
14

Least common multiple 5, 8, 4

Mathematics
1 answer:
AlekseyPX3 years ago
5 0

Step-by-step explanation:

The LCM of 4,5,8 4 , 5 , 8 is 2⋅2⋅2⋅5=40 2 ⋅ 2 ⋅ 2 ⋅ 5 = 40 .

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What mistake did the student make in this one-step equation?
MArishka [77]

Answer:

C

Step-by-step explanation:

19-8=11.

7 0
3 years ago
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Calculator
Sedaia [141]

Check the picture below.

so let's find the lengths of those two sides in red, since are the length and width of the rectangle.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-6}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{-3}~,~\stackrel{y_2}{6})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d = \sqrt{[-3-(-6)]^2+[6-3]^2}\implies d=\sqrt{(-3+6)^2+(6-3)^2} \\\\\\ d=\sqrt{9+9}\implies \boxed{d=\sqrt{18}} \\\\[-0.35em] ~\dotfill

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-6}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-1})~\hfill d=\sqrt{[-2-(-6)]^2+[-1-3]^2} \\\\\\ d=\sqrt{(-2+6)^2+(-1-3)^2}\implies d=\sqrt{16+16}\implies \boxed{d=\sqrt{32}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{area of the rectangle}}{(\sqrt{18})(\sqrt{32})}\implies \sqrt{18\cdot 32}\implies \sqrt{576}\implies 24

7 0
4 years ago
Compound interest of $1000 is invested at 10% compounded continuously, the future value s at any time t in years is given by s=1
crimeas [40]

Answer: 6.93 years

Step-by-step explanation:

Given

Rate of interest is r=10\%

Future value is given by s=1000e^{0.1t}

For the investment to double itself, i.e. s=2000

\Rightarrow 2000=1000e^{0.1t}\\\Rightarrow 2=e^{0.1t}\\\\\text{Taking log both sides}\\\\\Rightarrow \ln 2=0.1t\\\\\Rightarrow t=\dfrac{\ln 2}{0.1}\\\\\Rightarrow t=6.93\ \text{years}

It takes around 6.93 years to double the investment.

8 0
3 years ago
In the figure below, segment CD is parallel to segment EF and point H bisects segment DE :
Grace [21]

Answer:

See explanation

Step-by-step explanation:

In the figure below, segment CD is parallel to segment EF, DE is a transversal, then angles DIH and HGI are congruent as alternate interior angles when two parallel lines are cut by a transversal.

Consider triangles DIH and EGH. In these triangles,

  • \angle DIH\cong \angle EGH as alternate interior angles;
  • \angle DHI\cong \angle GHE as vertical angles;
  • DH\cong HE because point H bisects segment DE (given).

Thus,

\triangle DIH\cong \triangle EGH by AAS postulate

4 0
3 years ago
Tamica is making a fruit salad. She spends $3.30 on 6 kiwis, $8.40 on 3 pounds of grapes and $8.54 for 7 bananas.
Ludmilka [50]

Answer: how come you don't know the answer what grade are you in

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