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3 years ago

Graph the equations x = 3 and y=5.

Mathematics

1 answer:

inna [77]3 years ago

3 0

Answer:

plot points:

(0, 5)

(3, 5)

(3, 0)

Step-by-step explanation:

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Answer:

#1: x/4 - 3/4

#2: x/14 + 9/2

Step-by-step explanation:

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The equation that models the current water temperature t of the swimming pool is t -6=78 which best describes the error made whe

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1 year ago

Move values to the lines to complete the sentence about triangle p’ q’ r’

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2 years ago

A multiple-choice standard test contains total of 25 questions, each with four answers. Assume that a student just guesses on ea

weqwewe [10]

Answer:

a) 8*88*10⁻⁶ ( 0.00088 %)

b) 0.2137 (21.37%)

Step-by-step explanation:

if the test contains 25 questions and each questions is independent of the others, then the random variable X= answer "x" questions correctly , has a binomial probability distribution. Then

P(X=x)= n!/((n-x)!*x!)*p^x*(1-p)^(n-x)

where

n= total number of questions= 25

p= probability of getting a question right = 1/4

then

a) P(x=n) = p^n = (1/4)²⁵ = 8*88*10⁻⁶ ( 0.00088 %)

b) P(x<5)= F(5)

where F(x) is the cumulative binomial probability distribution- Then from tables

P(x<5)= F(5)= 0.2137 (21.37%)

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3 years ago

An eastbound train left at 12pm. Four hours later, a westbound train left the same station. At 8pm, the two trains were 400 mile

Ainat [17]

Answer:

Step-by-step explanation:

Gotta love these motion problems!

d = rt is what we need here to solve this, along with some logic.

If the EB (eastbound) train left at noon then at the end of its travels, at 8pm to be specific, it was traveling for 8 hours. Therefore, for the EB train, t = 8.

If the WB train left at 4 pm then at the end of its travels, also at 8pm, it was traveling for 4 hours. Therefore, for the WB train, t = 4.

The distance between the trains is given as 400 miles. That 400 mile distance is due to the fact that each train traveled a distance of rate*time. The distance the WB train traveled + the distance the EB train traveled = 400 miles. Now we just need to find out the distance each traveled in its respective time frame.

For the EB train. We already know that t = 8. We do not know how fast it's going, so rate is just r. In the distance formula, d = rt:

$d_{EB}=8r$

For the WB train. We already know that t = 4. We do not know this rate either, but we do know that it is traveling 10 mph faster than the EB train, so rate is r + 10. In the distance formula, d = rt:

$d_{WB}=4(r+10)$ and