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Finger [1]
3 years ago
13

Pelase i need help on this

Mathematics
1 answer:
Margaret [11]3 years ago
8 0

Answer:

2x+y=105 and x+4y=105 are the system of equations that can be used to find the cost of each item

Step-by-step explanation:

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Andrea earns a monthly salary of $3425 plus 2% commission. Last month, she sold $14,624 worth of products.
Nastasia [14]
The answer would be $3737.48.
7 0
3 years ago
write a compound inequality to represent passing grades are greater than or equal to 65 and less than or equal to 100 where x re
balandron [24]
Answer:
65 < or equal to x > or equal to 100

Ps: had to put "or equal to", because I can't put the lines underneath

Anyways, when an inequality says and, it is automatically a compound inequality. The x is in the middle.
8 0
4 years ago
Find the perimeter of the shape on the right.
SCORPION-xisa [38]

Here is what to do:

Add like terms. For example, you can add apples to apples, but not apples to oranges. In other words, you can add similar values of x with its others, but not the values of x with regular numbers.

The answer is 3x-3

5 0
3 years ago
Twenty identical looking packets of white power are such that 15 contain cocaine and 5 do not. Four packets were randomly select
xxMikexx [17]

Answer:

The probability of selecting randomly 6 packets such that the first 4 contain cocaine and 2 not is 0.3522.

Step-by-step explanation:

Probabilities of selecting 4 packets with the ilegal substance:

(\frac{15}{4})\\= \frac{15!}{4!(15-4)!}

Combinassions possible= 1365

Probabilities of selecting 2 packets with white powder:

(\frac{5}{2})= \frac{5!}{2!(5-2)!}

Combinations possible= 10

Probabilities of selecting 6 packets from the totality of them:

(\frac{20}{6}) = \frac{20!}{6!(20-6)!}

Combinations possible= 38760

The probability of picking 4 with the substance and 2 with only white powder is:

\frac{(15ncr4)(5ncr2)}{(20ncr6)} = 0.3522

I hope this answer helps you.

6 0
3 years ago
What is Your Budget?
yan [13]
Option 1 I think i’m not positive though
7 0
3 years ago
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