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2 years ago

1Q: i will answer your questions if mark ME Brainleist

Mathematics

2 answers:

masha68 [24]2 years ago

7 0

Wut Σ(￣。￣ノ)ノ.........

crimeas [40]2 years ago

4 0

Answer:

This makes no sense pls repeat the question

Step-by-step explanation:

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Find the height of the triangle.

Ierofanga [76]

Answer:

The value of x = 3.42

Step-by-step explanation:

Formula:

Sin ∅ = Opposite side /Hypotenuse

From the figure we can see a right angled triangle.

One angle is given, hypotenuse = 10 and height = x.

To find the value of x

sin 20 = Opposite side/hypotenuse = x/10

x = 10 * sin 20

= 10 * 0.342 = 3.42

Therefore the value of x = 3.42

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3 years ago

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Which number produces a rational number when added to 0.42

kenny6666 [7]

Any Whole or Rational Number, 1 can be used as an Example if you want it Simple

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2 years ago

I need help please!!

dalvyx [7]

Answer:

y=1/2x +2

Step-by-step explanation:

1/2 is the slope, 2 is the y intercept.

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2 years ago

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pav-90 [236]

Step-by-step explanation:

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2 years ago

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Find the least common multiple (LCM) of 8y^6+ 144y^5+ 640y^4 and 2y^4 + 40y^3 + 200y^2.

Mice21 [21]

Answer:

LCM = $8y^{4}(y+ 10)^{2}(y + 8)$

Step-by-step explanation:

Making factors of $8y^{6}+ 144y^{5}+ 640y^{4}$

Taking $8y^{4}$ common:

$\Rightarrow 8y^{4} (y^{2}+ 18y+ 80)$

Using factorization method:

$\Rightarrow 8y^{4} (y^{2}+ 10y + 8y + 80)\\\Rightarrow 8y^{4} (y (y+ 10) + 8(y + 10))\\\Rightarrow 8y^{4} (y+ 10)(y + 8))\\\Rightarrow \underline{2y^{2}} \times 4y^{2} \underline{(y+ 10)}(y + 8)) ..... (1)$

Now, Making factors of $2y^{4} + 40y^{3} + 200y^{2}$

Taking $2y^{2}$ common:

$\Rightarrow 2y^{2} (y^{2}+ 20y+ 100)$

Using factorization method:

$\Rightarrow 2y^{2} (y^{2}+ 10y+ 10y+ 100)\\\Rightarrow 2y^{2} (y (y+ 10) + 10(y + 10))\\\Rightarrow \underline {2y^{2} (y+ 10)}(y + 10) ............ (2)$

The underlined parts show the Highest Common Factor(HCF).

i.e. HCF is $2y^{2} (y+ 10)$ .

We know the relation between LCM, HCF of the two numbers 'p' , 'q' and the numbers themselves as:

$HCF \times LCM = p \times q$

Using equations (1) and (2): $\Rightarrow 2y^{2} (y+ 10) \times LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times 2y^{2} (y+ 10)(y + 10)\\\Rightarrow LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times (y + 10)\\\Rightarrow LCM = 8y^{4}(y+ 10)^{2}(y + 8)$

Hence, LCM = $8y^{4}(y+ 10)^{2}(y + 8)$

5 0

2 years ago