1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vikki [24]
3 years ago
15

Write a program that will ask the user for a set of ten numbers. After all ten numbers have been entered, the program will displ

ay the largest and smallest numbers of the data set. The program will then prompt the user whether he/she would like to enter another set of data. When the user indicates he/she is finished entering data sets, the program will finally display the average largest number and the average smallest number for all sets entered.
Computers and Technology
1 answer:
muminat3 years ago
8 0

Answer:

In Python:

nums = []

larg= []

small = []

while True:

   for i in range(10):

       num = int(input(": "))

       nums.append(num)

   print("Smallest: "+str(min(nums))); print("Largest: "+str(max(nums)))

   larg.append(max(nums))

   small.append(min(nums))

   another = int(input("Press 1 to for another sets: "))

   nums.clear()

   if not another == 1:

       break

   

print("Average Large: "+str(sum(larg)/len(larg)))

print("Average Small: "+str(sum(small)/len(small)))

Explanation:

This initializes the list of input numbers

nums = []

This initializes the list of largest number of each input set

larg= []

This initializes the list of smallest number of each input set

small = []

This loop is repeated until, it is exited by the user

while True:

The following iteration is repeated 10 times

   for i in range(10):

Prompt the user for input

       num = int(input(": "))

Add input to list

       nums.append(num)

Check and print the smallest using min; Check and print the largest using max;

   print("Smallest: "+str(min(nums))); print("Largest: "+str(max(nums)))

Append the largest to larg list

   larg.append(max(nums))

Append the smallest to small list

   small.append(min(nums))

Prompt the user to enter another set of inputs

   another = int(input("Press 1 to for another sets: "))

Clear the input list

   nums.clear()

If user inputs anything other than 1, the loop is exited

<em>    if not another == 1:</em>

<em>        break</em>

Calculate and print the average of the set of large numbers using sum and len    

print("Average Large: "+str(sum(larg)/len(larg)))

Calculate and print the average of the set of smallest numbers using sum and len

print("Average Small: "+str(sum(small)/len(small)))

You might be interested in
___ refers to all aspects of managing and processing information using computers and computer networks
Leokris [45]
<u>Information technology</u><u /> refers to all aspects of managing and processing information using computers and computer networks.
5 0
3 years ago
Cobbling together elements from the previous definition and whittling away the unnecessary bits leaves us with the following def
pentagon [3]

Answer:

This is not plagiarism

Explanation:

The student has properly referenced the original source material, therefore, it is not plagiarism. Also, it is sufficient to just reference the attached source material author. Although it is implied that several other authors' material has been used in the source material, there is no need for the student to reference the other authors too.

3 0
3 years ago
Implement the Tollable interface. It provides one method, pay, that accepts an int (how many dollars to pay), and returns an int
AVprozaik [17]

Answer:

Answered below.

Explanation:

\**This is written in the Kotlin programming language.**/

interface Tollable{

fun pay(payInDollars: Int) : Int

}

\**Interfaces are used to declare properties and methods that are common to different classes. As a result different classes can extend one interface.

The properties and methods in an interface are not always initialized. Classes extending from the interface are responsible for initializing these properties and methods. In Kotlin, a class can extend from more than one interface.**/

8 0
3 years ago
Create an instance of your queue that accepts java.lang.String Objects. Starting with an empty queue, use the enqueue(E e) metho
Aleksandr-060686 [28]

Answer:

Code is given below:

Explanation:

ode.java:

public class Node

{

String data;

Node next;

Node prev;

public Node(String data,Node next, Node prev){

this.next=next;

this.data=data;

this.prev=prev;

}

public Node(){

}

public String getData(){

return data;

}

public void setData(String data){

this.data=data;

}

public Node getNext(){

return next;

}

public void setNext(Node next){

this.next=next;

}

public Node getPrev(){

return prev;

}

public void setPrev(Node prev){

this.prev=prev;

}

}

Linked Queue.java:

public class LinkedQueues {

    Node head ;

   Node tail;

int size=0;

public Oueues(){

   this.head=null;

   this.tail=null;

}

public boolean isEmpty()

{

   return head == tail;

}    

 public int getSize()

    {

          return size;

  }    

 public void insert(String data){

   Node tmp = new Node(data,null,null);

    tmp.data=data;

    tmp.next=null;

    if(head==null){

        head=tail=tmp;

        head.prev=null;

    }

    else{

        tail.next=tmp;

        tmp.prev=tail;

        tail=tmp;

 }    

 }

 public String remove(){

  if(head.next==tail)

      return null;// list empty

  Node tmp=head.next;

  head.next=tmp.next;

  tmp.next.prev=head;

  list();

  return tmp.data;

 }

 public void list(){

     System.out.println("Queues");

     if(size==0){

         System.out.println("İs Empty");

     }

    Node tmp=head;

    while(tmp !=tail.getNext()){

        System.out.println(tmp.getVeri()+" ");

      tmp= tmp.getNext();

    }

     System.out.println();

 }

Linkedstack.java:

public class LinkedStack {

Node head = null;

Node tail = null;

int size=0;

     public int getSize() {

    return size;

      }

  public boolean isEmpty()

      {

   return head == null;

   }    

 public void Push(String data) {

    tail = head;

   head = new Node(data,null,null);

   head.data=data;

   head.next= tail;

   head.prev = null;

   if(tail != null) {

       tail.prev=head;

   }

   size++;

 }

 public void Pop() {

   if (!isEmpty()) {

       head = head.next;   // delete first node

       size--;

   } else {

       System.out.println("İs Empty");

   }

}

  public void Top() {

   Node tmp = head;

   while (tmp != null) {

       System.out.println(tmp.getData());

       tmp = tmp.getNext();

   }

}

 }

ArrayBasedQueue.java

import java.util.LinkedList;

import java.util.Queue;

 

public class ArrayBasedQueue

{

 public static void main(String[] args)

 {

   Queue<Integer> q = new LinkedList<>();

 

   // Adds elements {0, 1, 2, 3, 4} to queue

   for (int i=0; i<5; i++)

    q.add(i);

 

   // Display contents of the queue.

   System.out.println("Elements of queue-"+q);

   int removedele = q.remove();

   System.out.println("removed element-" + removedele);

 

   System.out.println(q);

   int head = q.peek();

   System.out.println("head of queue-" + head);

 

   int size = q.size();

   System.out.println("Size of queue-" + size);

 }

}

ArrayBasedStack.java:

import java.io.*;

import java.util.*;

 

public class ArrayBasedStack

{

static void stack_push(Stack<Integer> stack)

{

for(int i = 0; i < 5; i++)

{

stack.push(i);

}

}

 

// Popping element from the top of the stack

static void stack_pop(Stack<Integer> stack)

{

System.out.println("Pop :");

 

for(int i = 0; i < 5; i++)

{

Integer y = (Integer) stack.pop();

System.out.println(y);

}

}

 }

TestTimes.java:

public class TestTimes implements TestTimesInterface

{

 public static enum TimeUnits {};

 public static enum MemoryUnits{};

}

Driver.java:

public class driver

{

public static void main(String args[])

{

   Scanner s = new Scanner(System.in);

   LinkedStack y = new LinkedStack();

   LinkedQueues k = new LinkedQueues();

   ArrayBasedStack as=new ArrayBasedStack();

     ArrayBasedQueue as=new ArrayBasedQueue();

   FileWriter fwy;

   FileWriter fwk;

   File stack = new File("stack.txt");

   if (!stack.exists()) {

       stack.createNewFile();

   } else {

       System.out.println("already exists ");

   }

   BufferedReader reader = null;

   reader = new BufferedReader(new FileReader(stack));

   String line = reader.readLine();

   while (line != null) {

       y.Push(line = reader.readLine());

       System.out.println(line);

   }

   File queue = new File("queue.txt");

   if (!queue.exists()) {

       queue.createNewFile();

   } else {

       System.out.println("already exists ");

   }

   BufferedReader read = null;

   read = new BufferedReader(new FileReader(queue));

   String lines = read.readLine();

   while (lines != null) {

       lines = read.readLine();

       k.insert(lines);

       System.out.println(lines);

   }

int choice;

     System.out.println("1. Stack out- queue add");

     System.out.println("2. Stack add- queue out");

     System.out.println("3. Stack and queue ");

     System.out.println("4. File writer");

     choice = s.nextInt();

   switch (choice) {

       case 1:

           k.insert(s.next());

           k.list();

           y.pop();

           break;

       case 2:

         y.Push(s.next());

           y.Top();

         k.remove();

           break;

       case 3:

           y.Top();

           k.list();

           break;

       case 4:

           fwy = new FileWriter(stack);

           Node no = y.head;

           while (no.next != null) {

               fwy.write("\n" + no.data);

               no = no.next;

           }

           fwy.flush();

           fwy.close();

           fwk = new FileWriter(queue);

           Node noo = k.head;

           while (noo.next != null) {

               fwk.write("\n" + noo.data);

               noo = noo.next;

           }

           fwk.flush();

           fwk.close();

           break;

        }

 

}

}

6 0
3 years ago
Your company has a team of remote workers that need to use Windows-based software to develop company applications, but your team
timofeeve [1]

Operating systems are the software that supports the basic functioning of the computer. Windows Virtual Desktop is an Azure compute service that will help solve the problem.

<h3>What is Windows Virtual Desktop?</h3>

Windows Virtual Desktop is an app virtualization service of Azure that operates on the cloud platform. It includes standard operating procedures that can be used by users with multiple OS.

Azure's Virtual Desktop supports different versions of window OS. This type of system is majorly used in remote work demands and specialized workloads.

Therefore, Windows Virtual Desktop is an Azure compute service.

Learn more about Azures service here:

brainly.com/question/13144160

#SPJ1

5 0
2 years ago
Other questions:
  • Match each feature to whether it influences audio or video quality
    6·1 answer
  • What event in the 1970s contributed to the current
    6·2 answers
  • If you wanted to create a graph that showed how much each value contributed to the whole value, you would use a _____.
    15·2 answers
  • On a hard disk each track is divided into invisible wedge-shaped sections called _______
    15·1 answer
  • Using a cell phone while operating a motor vehicle is considered distraction because
    8·1 answer
  • How to get the home button on your screen?
    13·1 answer
  • Write a game that plays many rounds of Rock Paper Scissors. The user and computer will each choose between three items: rock (de
    8·1 answer
  • Which are examples of types of audio media that can support a presentation? Check all that apply.
    14·2 answers
  • How many MB are there in 1000 KB?
    11·2 answers
  • To set up scenarios,then set up a list, then set up the reference cell. to set up the cells that display the output results from
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!