1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vikki [24]
3 years ago
15

Write a program that will ask the user for a set of ten numbers. After all ten numbers have been entered, the program will displ

ay the largest and smallest numbers of the data set. The program will then prompt the user whether he/she would like to enter another set of data. When the user indicates he/she is finished entering data sets, the program will finally display the average largest number and the average smallest number for all sets entered.
Computers and Technology
1 answer:
muminat3 years ago
8 0

Answer:

In Python:

nums = []

larg= []

small = []

while True:

   for i in range(10):

       num = int(input(": "))

       nums.append(num)

   print("Smallest: "+str(min(nums))); print("Largest: "+str(max(nums)))

   larg.append(max(nums))

   small.append(min(nums))

   another = int(input("Press 1 to for another sets: "))

   nums.clear()

   if not another == 1:

       break

   

print("Average Large: "+str(sum(larg)/len(larg)))

print("Average Small: "+str(sum(small)/len(small)))

Explanation:

This initializes the list of input numbers

nums = []

This initializes the list of largest number of each input set

larg= []

This initializes the list of smallest number of each input set

small = []

This loop is repeated until, it is exited by the user

while True:

The following iteration is repeated 10 times

   for i in range(10):

Prompt the user for input

       num = int(input(": "))

Add input to list

       nums.append(num)

Check and print the smallest using min; Check and print the largest using max;

   print("Smallest: "+str(min(nums))); print("Largest: "+str(max(nums)))

Append the largest to larg list

   larg.append(max(nums))

Append the smallest to small list

   small.append(min(nums))

Prompt the user to enter another set of inputs

   another = int(input("Press 1 to for another sets: "))

Clear the input list

   nums.clear()

If user inputs anything other than 1, the loop is exited

<em>    if not another == 1:</em>

<em>        break</em>

Calculate and print the average of the set of large numbers using sum and len    

print("Average Large: "+str(sum(larg)/len(larg)))

Calculate and print the average of the set of smallest numbers using sum and len

print("Average Small: "+str(sum(small)/len(small)))

You might be interested in
Pick the 3 correct Python functions that parse and output only the date and time part of each log in log.txt as follows.
Mila [183]

Answer:

1, 4, 5

Explanation:

parse2:

. In this case it's passing "r" as an argument, which really does absolutely nothing, because whenever you call open("file.txt") it defaults to reading mode, so all you're doing is explicitly passing the "r". So let's look at the first line. Whenever you call str.split() without any arguments, by default it splits it by empty text, and filters any empty text. So str.split() is not the same as str.split(" ") although it has similar behavior. "     ".split(" ") will output ['', '', '', '', '', ''], while "     ".split() will output []. So in this case the line.split() will split the string '10.1.2.1 - car [01/Mar/2022:13:05:05  +0900] "GET /python HTTP/1.0" 200 2222' into the list<em> ['10.1.2.1', '-', 'car', '[01/Mar/2022:13:05:05', '+0900]', '"GET', '/python', 'HTTP/1.0"', '200', '2222'].</em> As you can see the the data is split into two pieces of text, AND they include the brackets in both strings. So when it gets the 3 index and strips it of the "[]" it will have the incomplete date

parse3:

 In this instance the "r" does nothing as mentioned before the "r" is already defaulted whenever you call open("file.txt") so open("file.txt") is the same as open("file.txt", "r"). So in this case we won't be working left to right, we're going inside the brackets first, kind of like in math you don't don't work left to right in equation 3 + 3(2+3). You work in the brackets first (inside brackets you do left to right). So the first piece of code to run is the line.split("[" or "]"). I actually kind of misspoke here. Technically the "[" or "]" runs first because this doesn't do what you may think it does. The or will only return one value. this is not splitting the line by both "[" and "]". The, or will evaluate which is true from left to right, and if it is true, it returns that. Since strings are evaluated on their length to determine if they're true. the "[" will evaluate to true, because any string that is not empty is true, if a string is empty it's false. So the "[" will evaluate to true this the "[" or "]" will evaluate to "[". So after that the code will run line.split("[") which makes the list: <em>['10.1.2.1 - car ', '01/Mar/2022:13:05:05  +0900] "GET /python HTTP/1.0" 200 2222']</em>. Now the [3:5] will splice the list so that it returns a list with the elements at index 3 (including 3) to 5 (excluding 5). This returns the list: [], because the previous list only has 2 elements. There are no elements at index 3 to 5 (excluding 5). So when you join the list by " ", you'll get an empty string

parse4:

  So I'm actually a bit confused here, I thought the "r+" would open the file in read-writing mode, but maybe this is a different version of python I have no idea, so I'm going to assume it is reading/writing mode, which just means you can read and write to the file. Anyways when you split the line by doing line.split(), as mentioned before it will split by empty spaces and filter any empty spaces. This line will return: <em>['10.1.2.1', '-', 'car', '[01/Mar/2022:13:05:05', '+0900]', '"GET', '/python', 'HTTP/1.0"', '200', '2222']</em>. and then you splice the list from indexes 3 to 5 (excluding 5). This will return the list: <em>['[01/Mar/2022:13:05:05', '+0900]']</em> which has the two pieces of information you need for the date. Now it joins them by a space which will output: '[01/Mar/2022:13:05:05 +0900]'. Now when you strip the "[]" you get the string: '01/Mar/2022:13:05:05 +0900' which is the correct output!

parse 5:

 So in this example it's using re.split. And the re.split is splitting by "[" or "]" which is what re.split can be used for, to split by multiple strings, which may be confused by string.split("[" or "]") which is not the same thing as explained above what the latter does. Also the reason there is a backslash in front of the [ and ] is to escape it, because normally those two characters would be used to define a set, but by using a \ in front of it, you're essentially telling regex to interpret it literally. So in splitting the string by "[" and "]" you'll get the list: <em>['10.1.2.1 - car ', '01/Mar/2022:13:05:05  +0900', ' "GET /python HTTP/1.0" 200 2222']</em> which has 3 elements, since it was split by the [ and the ]. The second element has the date, so all you need to do is index the list using the index 1, which is exactly what the code does

8 0
1 year ago
Unit 6: Lesson 2 - Coding Activity 1 AP Computer science
sladkih [1.3K]

The complete program is to define a boolean method that returns true if all elements of an array are negative, or return false, if otherwise

The method in java, where comments are used to explain each line is as follows:

//This defines the method

public static boolean chkNegative (double[] myArr) {

   //This initializes a boolean variable

   boolean isNeg = true;

   //This iterates through the array

   for (int i = 0; i < myArr.length; i++) {

     //If the array element is 0 or positive

     if (myArr[i] >= 0) {

         //Then the boolean variable is set to false

       isNeg = false;

       //And the loop is exited

       break;

     }

   }

   //This returns true or false

   return isNeg;

 }

Read more about boolean methods at:

brainly.com/question/18318709

8 0
3 years ago
Prostate cancer can physically affect both men and women
Naddika [18.5K]
Correct but men are more prone to it.
7 0
3 years ago
ZigBee is an 802.15.4 specification intended to be simpler to implement, and to operate at lower data rates over unlicensed freq
never [62]

Answer:

True

Explanation:

Solution

ZigBee uses unlicensed frequency bands but operate at slower speed or data rates.

ZigBee: This communication is particular designed for control and sensor networks on IEEE 802.15.4 requirement for wireless personal area networks (WPANs), and it is a outcome from Zigbee alliance.

This communication level defines physical and  (MAC) which is refereed to as the Media Access Control layers to manage many devices at low-data rates.

6 0
3 years ago
Advantages of desktop publishing over traditional methods include       
Licemer1 [7]
From what my teacher taught us it would be c.
6 0
3 years ago
Other questions:
  • What is FireWire?
    7·2 answers
  • Constructors have the same name as the ____.1. data members2. member methods3. class4. package
    5·1 answer
  • How can you remove heat from a computer?
    10·1 answer
  • To determine the average of a range of numbers, click the ____ in the formula bar, then click average.
    13·1 answer
  • Biomimicry is the term used when engineers are inspired by objects found in nature? Group of answer choices True False
    10·1 answer
  • Is there any quantum computer in India?​
    9·1 answer
  • Which type of boot authentciation is more secure?
    10·1 answer
  • HELPPP PLEASE <br><br> Html can be used to create complicated mobile applications <br> True or false
    10·1 answer
  • Which statement is true about encoding in Python?
    7·1 answer
  • Tick the best alternatives 1. Which one of the following is input device? a) Speaker b) Printer c. Monitor d. Mouse​
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!