Question

The sum of three consecutive integers is more than 62. Write an inequality to represent the above

Answer 1

Given:

Sum of three consecutive integers is more than 62.

To find:

The inequality to represent the above  situation then solve your inequality.

Solution:

Let the three consecutive integers are $x,x+1,x+2$ respectively.

Sum of three consecutive integers is more than 62. So,

$x+(x+1)+(x+2)>62$

$3x+3>62$

Subtract 3 from both sides.

$3x>62-3$

$3x>59$

Divide both sides by 3.

$x>\dfrac{59}{3}$

Therefore, the required inequality is $x+(x+1)+(x+2)>62$ and solution is $x>\dfrac{59}{3}$.