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7nadin3 [17]
3 years ago
9

The sum of three consecutive integers is more than 62. Write an inequality to represent the above

Mathematics
1 answer:
Mandarinka [93]3 years ago
3 0

Given:

Sum of three consecutive integers is more than 62.

To find:

The inequality to represent the above  situation then solve your inequality.

Solution:

Let the three consecutive integers are x,x+1,x+2 respectively.

Sum of three consecutive integers is more than 62. So,

x+(x+1)+(x+2)>62

3x+3>62

Subtract 3 from both sides.

3x>62-3

3x>59

Divide both sides by 3.

x>\dfrac{59}{3}

Therefore, the required inequality is x+(x+1)+(x+2)>62 and solution is x>\dfrac{59}{3}.

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