If the likelihood of boys being born is 56%, then the complement of that is the likelihood of girls being born which is 100% - 56% = 44%.
Since we are given that of the baby girls born, 12% are premature, the probability of a premature baby girl being born is:
(0.44)(0.12) = 0.0528 or 5.28%
The closest answer is the FIRST OPTION (5%).
Answer:
y = 1/2x - 5
Step-by-step explanation:
I'm going to use slope-intercept form. Your y-intercept is already shown when x is zero, which is (0,-5). Your slope is defined as rise over run, so 1/2 in this case. This gives you an equation of f(x) = 1/2x-5
Your anbswer is gonna be 5,7
The answer is 3 radical 6 over 4
See attached pic