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3 years ago

Sandra rolls 2 fair dice. What is the probability of both dice showing a different number?

Mathematics

1 answer:

IRINA_888 [86]3 years ago

8 0

Answer:

Each one has 3 even and 3 odd numbers.

For the first one to be even there is a 3/6 probability, which reduces to 1/2.

The probability of the second one being even is also 1/2.

The probability of both being even would be 1/2 x 1/2 = 1/4 probability

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Max is thinking of a number which he calls n

Drupady [299]

Answer:

what are you trying to ask?

Step-by-step explanation:

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3 years ago

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What is 3x + 4y = 8 in slope-intercept form?

Sauron [17]

Answer:

y = -3/4x + 2

Step-by-step explanation:

3x + 4y = 8

Objective:

To turn it into y =mx + b

Rearrange:

3x + 4y = 8

4y = -3x + 8

y = -3/4 x + 8/4

y = -3/4x + 2

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3 years ago

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A scientist claims that 7% 7 % of viruses are airborne. If the scientist is accurate, what is the probability that the proportio

Reptile [31]

Answer:

The probability is $P(|p-\^{p}| > 0.03) = 0.0040$

Step-by-step explanation:

From the question we are told that

The population proportion is $p = 0.07$

The mean of the sampling distribution is $\mu_p = 0.07$

The sample size is n = 600

Generally the standard deviation is mathematically represented as

$\sigma_p = \sqrt{\frac{p (1 -p)}{n} }$

=> $\sigma_p = \sqrt{\frac{0.07(1 -0.07)}{600} }$

=> $\sigma_p = 0.010416$

Generally the probability that the proportion of airborne viruses in a sample of 600 viruses would differ from the population proportion by greater than 3% is mathematically represented as

$P(|p-\^{p}| > 0.03) = 1 - P(|p -\^{p}| \le 0.03)$

=> $P(|p-\^{p}| > 0.03) = 1 - P(-0.03 \le p -\^{p} \le 0.03 )$

Now add p to both side of the inequality

=> $P(|p-\^{p}| > 0.03) = 1 - P( 0.07-0.03 \le \^{p} \le 0.03+ 0.07 )$

=> $P(|p-\^{p}| > 0.03) = 1 - P(0.04 \le \^{p} \le 0.10 )$

Now converting the probabilities to their respective standardized score

=> $P(|p-\^{p}| > 0.03) = 1 - P(\frac{0.04 - 0.07}{0.010416} \le Z \le \frac{0.10 -0.07}{0.010416} )$

=> $P(|p-\^{p}| > 0.03) = 1 - P(-2.88 \le Z \le 2.88 )$

=> $P(|p-\^{p}| > 0.03) = 1 - [P(Z \le 2.88) - P(Z \le -2.88)]$

From the z-table

$P(Z \le 2.88) = 0.9980$

and

$P(Z \le -2.88) = 0.0020$

$P(|p-\^{p}| > 0.03) = 1 - [0.9980 - 0.0020]$

=> $P(|p-\^{p}| > 0.03) = 0.0040$

7 0

3 years ago

5/7 + 1/7<br> Put in simplest form please!

Rasek [7]

Answer:

6/7

Step-by-step explanation:

5/7 + 1/7

Since the denominators are the same, we just add the numerators

5+1 = 6

Then we put the numerator over the denominator

6/7

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4 years ago

Solve the simultaneous equations.

Vera_Pavlovna [14]

Answer:

x = 1.5 ; y = -0.5

Step-by-step explanation:

2x + 4y = 1 ---------------------(i)

3x - 5y =7 ----------------------(ii)

(i) * 5 10x + 20y = 5

(ii)*4 <u> 12x -20y = 28 </u>

add, 22x = 33 { here y will be eliminated}

x = 33/22 = 3/2

x = 1.5

Put the value of x in equation (i)

2*1.5 + 4y = 1

3 + 4y = 1

4y = 1-3

4y = -2

y = -2/4 = -1/2

y = -0.5

4 0

3 years ago