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ss7ja [257]
3 years ago
13

A new app was download 175 times in the first week. Since then the number of downloads has increased continuously by 16.5% each

week. What is the approximate number of times the app was downloaded after 12 weeks?
Mathematics
1 answer:
julia-pushkina [17]3 years ago
8 0

Answer:

Step-by-step explanation:

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How are the solutions to the inequality -3x>18 different from the solutions to -3x>18 ?
Novay_Z [31]

Answer:

x < -6

Step-by-step explanation:

 -3x > 18

Divide both sides by -3

-3x/-3 < 18/-3

Note : in inequalities when both sides are divided by negative or minus, the inequality sign changes.

Therefore

x < -6

There's no difference as the equations are the same

I hope this was helpful, please rate as brainliest

3 0
3 years ago
John purchased a carr in 1961 for $12,000. Experts estimate that its value will increase by 5% per year. How much will be the co
GuDViN [60]

Answer:

A- 35103$

Step-by-step explanation:

6 0
4 years ago
A plane flying horizontally at an altitude of 3 miles and a speed of 500 mi/h passes directly over a radar station. Find the rat
konstantin123 [22]

Answer:

The rate at which the distance from the plane to the station is increasing is 331 miles per hour.

Step-by-step explanation:

We can find the rate at which the distance from the plane to the station is increasing by imaging the formation of a right triangle with the following dimensions:

a: is one side of the triangle = altitude of the plane = 3 miles

b: is the other side of the triangle = the distance traveled by the plane when it is 4 miles away from the station and an altitude of 3 miles

h: is the hypotenuse of the triangle = distance between the plane and the station = 4 miles                    

First, we need to find b:    

a^{2} + b^{2} = h^{2}   (1)    

b = \sqrt{h^{2} - a^{2}} = \sqrt{(4 mi)^{2} - (3 mi)^{2}} = \sqrt{7} miles

Now, to find the rate we need to find the derivative of equation (1) with respect to time:

\frac{d}{dt}(a^{2}) + \frac{d}{dt}(b^{2}) = \frac{d}{dt}(h^{2})

2a\frac{da}{dt} + 2b\frac{db}{dt} = 2h\frac{dh}{dt}

Since "da/dt" is constant (the altitude of the plane does not change with time), we have:  

0 + 2b\frac{db}{dt} = 2h\frac{dh}{dt}

And knowing that the plane is moving at a speed of 500 mi/h (db/dt):

\sqrt{7} mi*500 mi/h = 4 mi*\frac{dh}{dt}

\frac{dh}{dt} = \frac{\sqrt{7} mi*500 mi/h}{4 mi} = 331 mi/h  

Therefore, the rate at which the distance from the plane to the station is increasing is 331 miles per hour.

I hope it helps you!

4 0
3 years ago
What is measure of angle KJL
Xelga [282]

Answer:

7x - 8.

Step-by-step explanation:

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5 0
3 years ago
The length of a photograph is 1 less than twice the width. The area is 45 cm squared. Find the dimensions of the photograph.
kkurt [141]

the lenght is 9 and the width is 5 so 9 by 5

7 0
4 years ago
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