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bixtya [17]
2 years ago
7

At the county fair, the Baxter family bought 6 hot dogs and 4 juice drinks for $16.70. The Farley family bought 3 hot dogs and 4

juice drinks for $10.85.
Which system of equations correctly represents this situation where x equals the price of a hot dog, and y equals the price of a juice drink?



A) 6x+4y=10.85
3x+4y=16.70


B)6x+4y=16.70

3x+4y=10.85


C) 4x+6y=16.70

4x+3y=10.85


D) 6x+3y=10.85

4x+4y=16.70
Mathematics
1 answer:
Lana71 [14]2 years ago
3 0

Answer: H- hot dogs

J- juice box

6h+4j=16.70

3h+4j=10.85

Elimination:

-6h-4j=-16.70

3h+4j=10.85

-3h=-5.85

H= 1.95

3(1.95)+4j=10.85

5.85+4j=10.85

4j=5

J=1.25

1.95 dollars for a hotdog and 1.25 dollars for a juice box

Step-by-step explanation:

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