At the county fair, the Baxter family bought 6 hot dogs and 4 juice drinks for $16.70. The Farley family bought 3 hot dogs and 4 juice drinks for $10.85. Which system of equations correctly represents this situation where x equals the price of a hot dog, and y equals the price of a juice drink?
A) 6x+4y=10.85
3x+4y=16.70
B)6x+4y=16.70
3x+4y=10.85
C) 4x+6y=16.70
4x+3y=10.85
D) 6x+3y=10.85
4x+4y=16.70
1 answer:
Answer: H- hot dogs
J- juice box
6h+4j=16.70
3h+4j=10.85
Elimination:
-6h-4j=-16.70
3h+4j=10.85
-3h=-5.85
H= 1.95
3(1.95)+4j=10.85
5.85+4j=10.85
4j=5
J=1.25
1.95 dollars for a hotdog and 1.25 dollars for a juice box
Step-by-step explanation:
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