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Mathematics

2 answers:

frozen [14]2 years ago

8 0

Answer:

X and Y = 4

Well, it's a right triangle. The red box means 90 degree angle. So I would say that all the sides are equal.

Vikki [24]2 years ago

4 0

HOPE THIS HELPS YOU...HAVE A NICE DAY...

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How to do I don't know how to do can u help me pls. Thanks you

melomori [17]

Alright.
So, we have 2185 student in Rose.
Lily School has 307 more students than Rose, so Lily has,
2185 + 307 = 2492 Students in Lily School.
Since question a. is asking you to round off to the nearest ten, your answer to part a is 2490.

For part b. add 2185 and 2490.
2185 + 2490 = 4675 students.
The questions want you to round to the nearest hundredth, so,
4700 is the answer to part b.

4 0

3 years ago

Read 2 more answers

Find the half range Fourier sine series of the function

worty [1.4K]

The full range is $-\pi$ (length $2L=2\pi$ ), so the half range is $L=\pi$ . The half range sine series would then be given by

$f(x)=\displaystyle\sum_{n\ge1}b_n\sin\dfrac{n\pi x}L=\sum_{n\ge1}b_n\sin nx$

where

$b_n=\displaystyle\frac2L\int_0^Lf(x)\sin\dfrac{n\pi x}L\,\mathrm dx=\frac2\pi\int_0^\pi(\pi-x)\sin nx\,\mathrm dx$

Essentially, this is the same as finding the Fourier series for the function

$\begin{cases}g(x)=\begin{cases}\pi-x&\text{for }0$

Integrating by parts yields

$b_n=\dfrac2\pi\left(\dfrac\pi n-\dfrac{\sin n\pi}{n^2}\right)=\dfrac2n$

So the half range sine series for this function is simply

$f(x)=\displaystyle\sum_{n\ge1}\frac{2\sin nx}n$