To represent this statement I put it in an expression thingy -3 ⩽ p <1
Answer:
1) C
2) F
3) A
Step-by-step explanation:
Given that : X = number of Wildlife raft Trips to be scheduled.
while Y = number of Group Sailing Lessons to be scheduled.
1) Constraint (1) : 120x + 160y ≥ 1800
Represents the Minimum revenue requirement
2) Constraint (4) : 6x ≥ 30
Represents The demand of raft trips that must be satisfied.
3) Constraint (6) : x + y ≤ 12
Represents The maximum number of captions who can be deployed.

(a)
![f'(x) = \frac{d}{dx}[\frac{lnx}{x}]](https://tex.z-dn.net/?f=f%27%28x%29%20%3D%20%5Cfrac%7Bd%7D%7Bdx%7D%5B%5Cfrac%7Blnx%7D%7Bx%7D%5D)
Using the quotient rule:


For maximum, f'(x) = 0;


(b) <em>Deduce:
</em>

<em>
Soln:</em> Since x = e is the greatest value, then f(e) ≥ f(x) > f(0)


, since ln(e) is simply equal to 1
Now, since x > 0, then we don't have to worry about flipping the signs when multiplying by x.



Taking the exponential to both sides will cancel with the natural logarithmic function in the right hand side to produce:


, as required.
Answer:
B.
Step-by-step explanation:
Just took it. Edg 2020. Hope this helps :)