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posledela
3 years ago
9

Write a real word problem that can be represented by the equation a - 6 = 15

Mathematics
2 answers:
chubhunter [2.5K]3 years ago
3 0

Answer: your friend is trying to find out how many canys are in a box(a) and he gives you 6 and has 15 left

Step-by-step explanation:

jeka943 years ago
3 0

Answer:

Step-by-step explanation:

I have done 6 problems from my homework today yet still have 15 homework problems to finish by tomorrow. How many homework problems I have been assigned in the begining of the day?

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Which function has a constant additive rate of change of –1/4? A coordinate plane with a straight line with a negative slope. Th
pickupchik [31]

Answer:

a) ◇G = ◇H - T◇S wiĺl be negative.

b) It will be a spontaneous reaction.  

Explanation:

As ◇H is less than 0 and T◇S is greater than 0 so if we put it in the equation we would get the negative maximum result. And when the energies are with negative sign they are said to be spontaneous.

3 0
3 years ago
Read 2 more answers
Math on the Spot For Problems 2-3, use conversion factors.
asambeis [7]
2. 120 feet
3. 5 us liquid gallons
7 0
3 years ago
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The first three terms of an arithmetic series are 6p+2, 4p²-10 and 4p+3 respectively. Find the possible values of p. Calculate t
Doss [256]

Answer:

First Case:

\displaystyle p=\frac{5}{2}\text{ and } d=-2

Second Case:

\displaystyle p=-\frac{5}{4}\text{ and } d=\frac{7}{4}

Step-by-step explanation:

We know that the first three terms of an arithmetic series are:

6p+2, 4p^2-10, \text{ and } 4p+3

Since this is an arithmetic sequence, each subsequent term is <em>d</em> more than the previous term, where <em>d</em> is our common difference.

Therefore, we can write the second term as;

4p^2-10=(6p+2)+d

And, likewise, for the third term:

4p+3=(6p+2)+2d

Let's solve for <em>d</em> for each of the equations.

Subtracting in the first equation yields:

d=4p^2-6p-12

And for the second equation:

2d=-2p+1

To avoid fractions, let's multiply the first equation by 2. Hence:

2d=8p^2-12p-24

Therefore:

8p^2-12p-24=-2p+1

Simplifying yields:

8p^2-10p-25=0

Solve for <em>p</em>. We can factor:

8p^2+10p-20p-25=0

Factor:

2p(4p+5)-5(4p+5)=0

Grouping:

(2p-5)(4p+5)=0

Zero Product Property:

\displaystyle p_1=\frac{5}{2} \text{ or } p_2=-\frac{5}{4}

Then, we can use the second equation to solve for <em>d</em>. So:

2d_1=-2p_1+1

Substituting:

\begin{aligned} 2d_1&=-2(\frac{5}{2})+1 \\ 2d_1&=-5+1 \\ 2d_1&=-4 \\ d_1&=-2\end{aligned}

So, for the first case, <em>p</em> is 5/2 and <em>d</em> is -2.

Likewise, for the second case:

\begin{aligned} 2d_2&=-2(-\frac{5}{4})+1 \\ 2d_2&=\frac{5}{2}+1 \\ 2d_2&=\frac{7}{2} \\ d_2&=\frac{7}{4}\end{aligned}

So, for the second case, <em>p </em>is -5/4, and <em>d</em> is 7/4.

By using the values, we can determine our series.

For Case 1, we will have:

17, 15, 13.

For Case 2, we will have:

-11/2, -15/4, -2.

8 0
3 years ago
In simplest radical form, what are the solutions to the quadratic equation 6 = x^2 – 10x?
Kamila [148]

Answer:x = 5+\sqrt{31},x = 5-\sqrt{31}

Step-by-step explanation:

7 0
4 years ago
Help with length of hypotenuse ​
Salsk061 [2.6K]

Answer:

sqrt(10) *x

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean theorem

a^2 + b^2 = c^2

x^2 + (3x)^2 = hypotenuse ^2

x^2 + 9x^2 = hypotenuse ^2

10x^2 = hypotenuse  ^2

Take the square root of each side

sqrt( 10x^2) =  sqrt(hypotenuse  ^2)

sqrt(10) * x = hypotenuse

5 0
3 years ago
Read 2 more answers
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