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Oduvanchick [21]

2 years ago

9

maya tried to play a new video game.on her first 4 tries,she lost 14 points,lost 8 points,and finnaly gave up.write and find the

value of an integer expression to show her final score

2 answers:

PilotLPTM [1.2K]2 years ago

5 0

Hello Bernadinnickesoxy30y!

I strongly believe the answer to your amazing question is -22.

Have a good day! -Wajiha

Pavel [41]2 years ago

4 0

-22 points is what she lost

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musickatia [10]

Answer:

Any multiple of 10

Step-by-step explanation:

A factor is defined as "a number or quantity that when multiplied with another produces a given number or expression." For example, the factors of 20 are 1, 2, 4, 5, 10, and 20.

When we multiply 2 and 5 together, we get 10. Multiplying this by anything else besides 0 will still yield something that has 2 and 5 as factors, for example 2 times 5 times 3 is 30. As this is just the same thing as multiplying 10 by 3, the answer is any multiple of 10.

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3 years ago

Given that cot θ = 1/√5, what is the value of (sec²θ - cosec²θ)/(sec²θ + cosec²θ) ?

Bogdan [553]

Step-by-step explanation:

$\mathsf{Given :\;\dfrac{{sec}^2\theta - co{sec}^2\theta}{{sec}^2\theta + co{sec}^2\theta}}$

$\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{{sec}\theta = \dfrac{1}{cos\theta}}}}$

$\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{co{sec}\theta = \dfrac{1}{sin\theta}}}}$

$\mathsf{\implies \dfrac{\dfrac{1}{cos^2\theta} - \dfrac{1}{sin^2\theta}}{\dfrac{1}{cos^2\theta} + \dfrac{1}{sin^2\theta}}}$

$\mathsf{\implies \dfrac{\dfrac{sin^2\theta - cos^2\theta}{sin^2\theta.cos^2\theta}}{\dfrac{sin^2\theta + cos^2\theta}{sin^2\theta.cos^2\theta}}}$

$\mathsf{\implies \dfrac{sin^2\theta - cos^2\theta}{sin^2\theta + cos^2\theta}}$

Taking sin²θ common in both numerator & denominator, We get :

$\mathsf{\implies \dfrac{sin^2\theta\left(1 - \dfrac{cos^2\theta}{sin^2\theta}\right)}{sin^2\theta\left(1 + \dfrac{cos^2\theta}{sin^2\theta}\right)}}$

$\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{cot\theta = \dfrac{cos\theta}{sin\theta}}}}$

$\mathsf{\implies \dfrac{1 -cot^2\theta}{1 + cot^2\theta}}$

$\mathsf{Given :\;cot\theta = \dfrac{1}{\sqrt{5}}}$

$\mathsf{\implies \dfrac{1 - \left(\dfrac{1}{\sqrt{5}}\right)^2}{1 + \left(\dfrac{1}{\sqrt{5}}\right)^2}}$

$\mathsf{\implies \dfrac{1 - \dfrac{1}{5}}{1 + \dfrac{1}{5}}}$

$\mathsf{\implies \dfrac{\dfrac{5 - 1}{5}}{\dfrac{5 + 1}{5}}}$

$\mathsf{\implies \dfrac{5 - 1}{5 + 1}}$

$\mathsf{\implies \dfrac{4}{6}}$

$\mathsf{\implies \dfrac{2}{3}}$

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2 years ago

The ratio 15:3 in its simplest

Gnoma [55]

Answer:

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Step-by-step explanation:

Divide each by 3.

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3 years ago

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