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SA = 2lw + 2lh + 2hw
SA = 2(15)(2) + 2(15)(6) + 2(6)(2)
SA = 60 + 180 + 24
SA = 264
Ok so the first thing to do would be get rid of the fraction. To do that multiply the ENTIRE equation but the denominator. Once all the numbers are multiplyed I think it’ll be easier for u to solve them :) or if u wanna solve them quick, download Photomath :)
yes, there are infinitety many polynomial that have exactly one real root just like your example, to determine the real root first let the real root is a, and the complex roots are b±ic the polynomial satisfy
-9x³ + 19x² + 17 = -(x - a)(x - b - ic)(x - b + ic)
9x³ - 19x² - 17 = (x - a)(x - b - ic)(x - b + ic)
Answer:
WHAT?
Step-by-step explanation:
