Answer:
324
Step-by-step explanation:
Answer:
The numerical limits for a B grade is between 81 and 89.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

B: Scores below the top 13% and above the bottom 56%
Below the top 13%:
Below the 100-13 = 87th percentile. So below the value of X when Z has a pvalue of 0.87. So below X when Z = 1.127. So




Above the bottom 56:
Above the 56th percentile, so above the value of X when Z has a pvalue of 0.56. So above X when Z = 0.15. So




The numerical limits for a B grade is between 81 and 89.
To solve this, you need to divide 127.5 by 51:
127.5/51 = 2.5
To find the percent, multiply 2.5 by 100:
2.5 x 100% = 250%
So 127.5 is 250% of 51
I believe there are 20 quarters and 3 nickels.....
Total value of the jar is $5.15.....
Quarters are worth 25 cents
And nickels are worth 5 cents.
First you know that there are 4 quarters in a dollar.
You have 5 dollars so you do 4 x 5 = 20
So five dollars ($5.00) is 20 quarters.
And you still have 15 cents left.
Because quarters are 25 cents the rest are nickels.
Nickels are worth 5 cents so you'd do 5 x 3 = 15.
15 cents!
Add all this together and get $5.15.
So your answer is
There are 20 quarters and 3 nickels in the jar.
Step-by-step explanation:
a1 = 2
a2 = a1 + 9 = 2 + 9 = 11
a3 = a2 + 9 = 20
a4 = a3 + 9 = 29
a5 = a4 + 9 = 38
a6 = a5 + 9 = 47