Can someone pleaseee help me i’ll give you brainliest
2 answers:
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Answer:
t = 6162 years
Step-by-step explanation:
This equation takes the form of
We are given everything but the amount of C-14 at time t = 0. But we can figure it out from the info we ARE given. We are told that when the spear head is found it contains 54% of its original amount of C-14. Notice we are dealing in percents. If 54% remains when it is found, it started out with 100% of its amount. That's our N value. Filling in:
Our goal is to get that t down from the exponential position that it is currently in. To do that we will need to eventually take the natural log of both sides, because ln's and e's "undo" each other, much like squaring "undoes" a square, or dividing "undoes" multiplication. So we take the natural log of both sides. On the right side, notice that when we take the natural log, the e disappears; it's "undone", gone. Before that, though, we will simplify by dividing both sides by 54. 100/54 = 1.851851852. So, altogether...
Simplifying by plugging the log of that number into our calculator, we get
.6161861395 = .0001t and
t = 6161.8613
Rounding to the nearest year, t = 6162 years
Answer:
68% of buyers paid between $147,700 and $152,300.
Step-by-step explanation:
We are given that prices of a certain model of a new home are normally distributed with a mean of $150,000.
Use the 68-95-99.7 rule to find the percentage of buyers who paid between $147,700 and $152,300 if the standard deviation is $2300.
<u><em>Let X = prices of a certain model of a new home</em></u>
SO, X ~ Normal()
The z score probability distribution for normal distribution is given by;
Z = ~ N(0,1)
where, = population mean price = $150,000
= standard deviation = $2,300
<u>Now, according to 68-95-99.7 rule;</u>
Around 68% of the values in a normal distribution lies between and
.
Around 95% of the values occur between and
.
Around 99.7% of the values occur between and
.
So, firstly we will find the z scores for both the values given;
Z = =
= -1
Z = =
= 1
This indicates that we are in the category of between and
.
SO, this represents that percentage of buyers who paid between $147,700 and $152,300 is 68%.