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8090 [49]
3 years ago
9

On Monday jack could lift 25lbs

Mathematics
1 answer:
kirill [66]3 years ago
3 0

Answer:

he can still lift 25 or more

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The difference of two complementary angles is 30 degrees. Find the measures of the angles.
oee [108]

Answer:

60 degrees and 30 degrees

Step-by-step explanation:

let the angles be x and y

we are given that the angles are complementary (i.e they sum up to 90 degrees). Hence we can write the first equation:

x + y = 90 ------(eq 1)

we are also given that the difference between the two angles is 30 degrees). Similarly we can write

x - y = 30 ------(eq 2)

now we have a system of 2 equations with 2 unknowns, which we can solve by elimination:

eq 1 + eq 2:

(x + y) + (x - y) = 90 + 30

2x = 120  (divide both sides by 2)

x = 120/2

x = 60 deg (substitute this back into eq 1)

x + y = 90

60 + y = 90 (subtract 60 from both sides)

y = 90 - 60

y = 30 deg.

4 0
3 years ago
X²+y²-6x+14y-1=0<br> and please show your work so I can learn
Eva8 [605]

Hello there,

I hope you and your family are staying safe and healthy during this winter season.

x^2 + y^2 -6x+14y-1=0

We need to use the Quadratic Formula*

x =\frac{-b+\sqrt{b^2}-4ac }{2a} , \frac{-b-\sqrt{b^2} -4ac }{2a}

Thus, given the problem:

a = 1, b=-6, c=y^2+14y-1

So now we just need to plug them in the Quadratic Formula*

x=\frac{6+2\sqrt{(-6)^2-4(y^2+14y-1)} }{2} , x=\frac{6-\sqrt{(-6)^2-4(y^2+14y-1)} }{2}

As you can see, it is a mess right now. Therefore, we need to simplify it

x=\frac{6+2\sqrt{10-y^2-14y} }{2}, x = \frac{6-2\sqrt{10-y^2-14y} }{2}

Now that's get us to the final solution:

x=3+\sqrt{10-y^2-14y}, x=3-\sqrt{10-y^2-14y}

It is my pleasure to help students like you! If you have additional questions, please let me know.

Take care!

~Garebear

3 0
3 years ago
The perimeter of a square is 420cm long. what is the length of each side?​
Zepler [3.9K]

Answer:

Each side of the square is 105cm long

Hope this helps.

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
the low temperature in colton for 5 days were -8 -13 -4 -9 and -16 what was the average low temperature for those 5 days
Andreas93 [3]
The average low temperature is -10.
-8+(-13)+(-4)+(-9)+(-16)= -50/5=-10
3 0
3 years ago
Read 2 more answers
Solve for x: 3 − (2x − 5) &lt; −4(x + 2)
Firdavs [7]

Answer:

A. x < -8 (first option)

Step-by-step explanation:

3 - (2x - 5) <  - 4(x + 2)

3 - 2x + 5 <  - 4x - 8

8 - 2x <  - 4x - 8

- 2x + 4x <  - 8 - 8

2x <  - 16

\boxed{\green{x <  - 8}}

6 0
3 years ago
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