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NikAS [45]
3 years ago
6

Answer each question.

Mathematics
1 answer:
Rama09 [41]3 years ago
6 0
All them would be equal to each other
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A container holds 8 gallons of water. It begins leaking at a constant rate. After 16 minutes the container has 6 gallons of wate
tangare [24]

In that 16 minutes, the amount that leaks out is (8 - 6) = 2 gallons.

The average unit rate of the leak is

          (2 gal)/(16 min) = (2/16) (gal/min) = 1/8 gal/min

                                                                = 16 fluid ounce per min

                                                                = 4/15 fl oz per second 
4 0
3 years ago
Read 2 more answers
Please, Please, Please brainers, help me solve this question. Thanks.
Dafna1 [17]
Answer:

440 square inches.

Explanation:

We can consider the boxes as one single shape.

So it's base area is 12×10=120 and the area of the side faces is 20×12=240 and 20×10=200.

Now, there are 2 of each, so let's add up everything and multiply by 2.

(120+240+200)×3=560 square inches.

But we have to take off the base, so:

560-120=440 square inches
3 0
4 years ago
What is the recursive formula for 3,7,11,15,...
scoundrel [369]

Arithmetic sequence: a_n=a_1+(n-1)d where: d = common difference between terms; n = term; a_1 = first term of sequence a_n = 3+(n-1)4 = 3+(4n-4) = 4n-1 Therefore, a_50 = 4(50)-1 = 200 - 1 = 199



8 0
4 years ago
In the figure below, solve for the value of b. b = ______ in. (round to the nearest tenth and do NOT include units in your answe
irakobra [83]

Answer:

255

Step-by-step explanation:

764

5 0
3 years ago
Verify which of the following are identities.
ch4aika [34]

Answer:

C

Step-by-step explanation:

Equation 1:

1+\frac{\cos^{2} \theta}{\cot^{2} \theta(1-\sin^{2} \theta)}\\ \\ 1+\frac{\sin^{2} \theta}{\cos^{2} \theta} \\ \\ 1+\tan^{2} \theta \\ \\ \sec^{2} \theta

Equation 2:

15\cos \theta \left(\frac{1}{\cos \theta}-\frac{\cot \theta}{\csc \theta} \right) \\ \\ 15\cos \theta \left(\frac{1}{\cos \theta}-\frac{\cos \theta / \sin \theta}{1/\sin \theta} \right) \\ \\ 15\cos \theta \left(\frac{1}{\cos \theta}-\cos \theta \right) \\ \\ 15\cos \theta \left(\frac{1-\cos^{2} \theta}{\cos \theta} \right) \\ \\ 15(1-\cos^{2} \theta) \\ \\ 15\sin^{2} \theta

6 0
2 years ago
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