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SSSSS [86.1K]
3 years ago
8

The population of a town is 14,000, and it grows at a rate of 4% per year. What will the population be in 6 years? What was the

population 6 years ago?
about 87,360; about 11,400

about 17,714; about 11,064

about 14,560; about 12,602

about 17,360; about 10,870
Mathematics
1 answer:
mario62 [17]3 years ago
8 0

Answer:

3rd one

Step-by-step explanation:

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Select the table representing a linear function. (Graph them if necessary.)
Neporo4naja [7]

Answer:

Option C

Step-by-step explanation:

the linear equation y = 2x+10 matches with option c

3 0
3 years ago
Complete the square to form a true equation;<br> x^2-2x+__=(x-__)^2
erica [24]

Answer:

see explanation

Step-by-step explanation:

To complete the square

add ( half the coefficient of the x- term )² to x² - 2x

x² + 2(- 1)x + 1

(x² - 2x + 1 = (x - 1)²

6 0
3 years ago
What is the inverse of y=2x^3 (cubed)
DIA [1.3K]
Switch places or x and y then solve it for y and you will get the inverse of the function,let me know if u have questions

3 0
3 years ago
The following octagon is formed by removing four congruent right triangles from a rectangle. What is the area of each triangle?
3241004551 [841]
Answer:
2 cm squared

Explanation:
The question asks for the area of each small triangle in the corners(meaning 1 triangle, not 4) as shown from the dotted lines. The area of a triangle is found by (base*height)/2.
Looking at the diagram, the triangle is 2 cm for both the base and height, and the hypotenuse is not labeled. Because it is a right triangle, 2 cm is also the height(the height is defined as an altitude from the tip of the triangle to the base using a right angle). So, height=2 and base=2.
Plug these numbers into the formula bh/2.
bh/2=?
(2)(2)/2=?
4/2=?
2=?
Each triangle has an area of 2 cm squared.
4 0
4 years ago
If C is the line segment from 7 3 to 0 0 find the value of the line integral C 4y2i xj dr
saul85 [17]
Parameterize C by

\mathbf r(t)=(x(t),y(t))=(1-t)(7,3)+t(0,0)=(7-7t,3-3t)

where 0\le t\le1. Then

\mathrm d\mathbf r=(-7\,\mathbf i-3\,\mathbf j)\,\mathrm dt

and the line integral is equivalent to

\displaystyle\int_C(4y^2\,\mathbf i+x\,\mathbf j)\cdot\mathrm d\mathbf r=\int_0^1(4(3-3t)^2\,\mathbf i+(7-7t)\,\mathbf j)\cdot(-7\,\mathbf i-3\,\mathbf j)\,\mathrm dt
\displaystyle=\int_0^1(-252t^2+525t-273)\,\mathrm dt=-\dfrac{189}2
7 0
3 years ago
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