Answer: The length of JF = 16 units.
Step-by-step explanation:
Given: In triangle DEF, segment DJ is a perpendicular bisector of side EF.
i.e. DJ is perpendicular to EF and DJ divides EF into two equal parts EJ and JF. [The perpendicular bisector is a line that is perpendicular to a line segment and splits it into two congruent segments.]
If EJ is 3y-8 and JF is 7y-40.
Then, 
![\Rightarrow\ 7y-3y=40-8\\\\\Rightarrow\ 4y=32\\\\\Rightarrow\ y=8 \text{ [Divide both sides by 4]}](https://tex.z-dn.net/?f=%5CRightarrow%5C%207y-3y%3D40-8%5C%5C%5C%5C%5CRightarrow%5C%204y%3D32%5C%5C%5C%5C%5CRightarrow%5C%20y%3D8%20%5Ctext%7B%20%5BDivide%20both%20sides%20by%204%5D%7D)
JF= 7(8)-40 =56-40= 16 units
Hence, the length of JF = 16 units.
Answer:
A
Step-by-step explanation:
I'm assuming by overlined you meant repeating as when there is a repeating number in a decimal, it has a line over it to represent such.
In the quotient of 4 divided by 7, there are zero numbers overlined. This is because the answer is .5714285714, no numbers are consecutively repeating for a long or the rest of the number.
Hope this helps!
The perimeter = 60+30+20+15+22+15+12+18+18 = 210m
so there is no enough fencing
A rectangle has a perimeter of 30 inches and it's [sic] dimensions are whole numbers what is the maximum possible area of the rectangle in square units
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P = 2(L + W) = 30
L + W = 15
<span>Max area --> 7*8 = 56 sq inches</span>
