In 4 hours Jessie can make 6 necklaces. How many necklaces can she make in 10 hours?

Mathematics

1 answer:

ad-work [718]3 years ago

6 0

Answer:

Step-by-step explanation:

in 8 hrs she can make 12 then cn only make one more so

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Suppose that scores on a knowledge test are normally distributed with a mean of 60 anda standard deviation of 4.3. Scores on an

Iteru [2.4K]

The Z-score for Boris is 1.627, and the Z-score value for the Callie is 1.267, Boris scored higher relatively.

The Z test is a parametric procedure that is used on data that is dispersed in a normal fashion. For testing hypotheses, the z test can be used on one sample, two samples, or proportions. When the population variance is known, it analyzes if the means of two big groups are dissimilar.

We know the formula for the Z-test:

$\rm Z = \dfrac{X-\mu}{\sigma}$

(a) For Boris:

$\rm Z = \dfrac{67-60}{4.3}$

Z = 1.627

(b) For Callie:

$\rm Z = \dfrac{119-110}{7.1}$

Z = 1.267

(c) Since the measures of two different data have been set to one measure and the value of the Z-score for Boris is higher relative to the Z-score value of Callie so Boris scored higher relatively.

Thus, the Z-score for Boris is 1.627, and the Z-score value for the Callie is 1.267, Boris scored higher relatively.

Learn more about the Z-test here:

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2 years ago

You make $422.79 a week. If you work 37 hours, find your hourly rate of pay.

marshall27 [118]

Answer:

11.43 per hour

Step-by-step explanation:

422.79/37=11.43

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3 years ago

What is the fastest or easiest Apex elective I need 1 more to graduate and am trying to be done by Oct 1st I have already done p

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Answer: Apex sucks tbh but i did psychology and it was pretty easy

Step-by-step explanation:

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3 years ago

An insurance company estimates 45 percent of its claims have errors. The insurance company wants to estimate with 99 percent con

nydimaria [60]

Answer:

We need a sample size of at least 657.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.