Answer:
0.82% probability that the average time it takes to complete both homework assignments is greater than 82 minutes
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Math homework:
Arts homework:
What is the probability that the average time it takes to complete both homework assignments is greater than 82 minutes?
Here, we have a sum of normal variables. The mean will be the sum of the means, while the standard deviation is the square root of the sum of the variances. So
This probability is 1 subtracted by the pvalue of Z when X = 82. So
has a pvalue of 0.9918
1 - 0.9918 = 0.0082
0.82% probability that the average time it takes to complete both homework assignments is greater than 82 minutes
I used the special right triangle rules for a 30-60-90 degree right triangle. The width of the park is 2 miles and the length of the sidewalk is 4 miles.
Answer:
51 milligrams
Step-by-step explanation:
Exponential growth or decay can be modeled by the equation ...
y = a·b^(x/c)
where 'a' is the initial value, 'b' is the "growth factor", and 'c' is the time period over which that growth factor applies. The time period units for 'c' and x need to be the same.
In this problem, we're told the initial value is a = 190 mg, and the value decays to 95 mg in 19 hours. This tells us the "growth factor" is ...
b = 95/190 = 1/2
c = 19 hours
Then, for x in hours the remaining amount can be modeled by ...
y = 190·(1/2)^(x/19)
__
After 36 hours, we have x=36, so the remaining amount is ...
y = 190·(1/2)^(36/19) ≈ 51.095 . . . . milligrams
About 51 mg will remain after 36 hours.
Answer:
what kind of work is this
Step-by-step explanation: