Quadratic formula is x = -b+ or- sq rt b^2-4ac / 2a
a=2 b=5 c=-3
-5 +or- sqrt 5^2-4(2)(-3) / 2(2)
-5 +or- sqrt 49/ 4
-5 + 7 /4 = 2/4 = 1/2
-5 - 7 /4 = -12/4 = -3
Factoring a*c is 2*-3 =-6
Factors of -6 that add to 5 are 6 and -1
Split 5x into +6x-1x
2x^2+6x-1x-3 and group
2x(x+3)-1(x+3)
(x+3)(2x-1)=0
x+3=0 gives x=-3
2x-1=0 gives x=1/2
I'm assuming the dimensions are like the measures of whatever the figure is. Volume, length,width,height,circumference,radius,diameter,area,perimeter,etc. whatever you are working with, that will help you find the dimensions of the figure:)
Answer:
90π units²
Step-by-step explanation:
(refer to attached)
Total Surface are off a right cylinder = area of its ends + area of curved surface
Given radius, r = 3 units and height, h = 12 units
Area of 2 ends,
= Area of 2 circles
= 2 x πr²
= 2π (3²)
= 2π (9)
=18π units²
Area of curved surface,
= 2πrh
= 2π(3)(12)
= 72π units²
Hence,
Surface area = 18π + 72π = 90π units²
