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2 years ago

ILL BRAINLIEST YOU PLEASE HELP ME

Mathematics

1 answer:

joja [24]2 years ago

6 0

Answer:

82°

Step-by-step explanation:

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A basketball rim 10 ft high casts a shadow 15 ft long. at the same time, a nearby building casts a shadow that is 54 ft long. ho

Tatiana [17]

15/10= 3/2
54/x=3/2
3× what=54
18
18×2= 36 ft the building is 36 ft

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3 years ago

Could 10.5 cm, 8.0 cm, and 4.0 cm be the lengths of a triangle

Aleksandr-060686 [28]

Answer

yes

Step-by-step explanation:

5 0

3 years ago

HELPPPP <br><br> When y=4x-6 find y if x=1/2

Gnom [1K]

Answer: y = -4

Step-by-step explanation:

y = 4x-6

y = 4(1/2)-6

y = 2-6

y = -4

7 0

3 years ago

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Quadrilateral ABCD is inscribed in a circle. What is the measure of angle A? Enter your answer in the box.

SashulF [63]

Answer:

135°

Step-by-step Explanation:

==>Given:

An inscribed quadrilateral ABCD with,

m<A = (3x +6)°

m<C = (x + 2)°

==>Required:

measure of angle A

==>Solution:

First, let's find the value of x.

Recall that the opposite angles in any inscribed quadrilateral in a circle are supplementary.

Therefore, this means m<A + m<C = 180°

Thus, (3x+6) + (x+2} = 180

3x + 6 + x + 2 = 180

Collect like terms:

3x + x + 6 + 2 = 180

4x + 8 = 180

Subtract 8 from both sides:

4x + 8 - 8 = 180 - 8

4x = 172

Divide both sides by 4:

4x/4 = 172/4

x = 43

We can now find m<A = (3x + 6)°

m<A = 3(43) + 6

= 129 + 6

measure of angle A = 135°

6 0

3 years ago

If 5 + 20 times 2 Superscript 2 minus 3 x Baseline = 10 times 2 Superscript negative 2 x Baseline + 5, what is the value of x? –

sp2606 [1]

Answer:

<h3>Option D) 3 is correct</h3><h3>Therefore the value of x is 3</h3>

Step-by-step explanation:

Given equation is $5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5$

<h3>To find the value of x :</h3>

First solving the given equation we have,

$5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5$

$5+20\times (2)^{2-3x}-5=10\times (2)^{-2x}+5-5$

$20\times (2)^{2-3x}=10\times (2)^{-2x}$

$20\times (2)^2.(2)^{-3x}=10\times (2)^{-2x}$

$20\times 4.(2)^{-3x}=10\times (2)^{-2x}$

$80(2)^{-3x}=10\times (2)^{-2x}$

$\frac{80}{10}(2)^{-3x}=\frac{10\times (2)^{-2x}}{10}$

$8(2)^{-3x}=(2)^{-2x}$

$\frac{(2)^{-3x}}{(2)^{-2x}}=\frac{1}{8}$

$(2)^{-3x}.(2)^{2x}=\frac{1}{2^3}$ ( by using the property $\frac{1}{a^{-m}}=a^m$ )

$2^{-3x+2x}=\frac{1}{2^3}$ ( by using the property $a^m.a^n=a^{m+n}$ )

$2^{-x}=\frac{1}{2^3}$

$\frac{1}{2^x}=\frac{1}{2^3}$ ( by using the property $a^{-m}=\frac{1}{a^m}$ )

Since bases are same so powers are same

Therefore we can equate the powers we get x=3

<h3>Therefore the value of x is 3</h3><h3>Option D) 3 is correct</h3>

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3 years ago

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