Answer:
0.1225
Step-by-step explanation:
Given
Number of Machines = 20
Defective Machines = 7
Required
Probability that two selected (with replacement) are defective.
The first step is to define an event that a machine will be defective.
Let M represent the selected machine sis defective.
P(M) = 7/20
Provided that the two selected machines are replaced;
The probability is calculated as thus
P(Both) = P(First Defect) * P(Second Defect)
From tge question, we understand that each selection is replaced before another selection is made.
This means that the probability of first selection and the probability of second selection are independent.
And as such;
P(First Defect) = P (Second Defect) = P(M) = 7/20
So;
P(Both) = P(First Defect) * P(Second Defect)
PBoth) = 7/20 * 7/20
P(Both) = 49/400
P(Both) = 0.1225
Hence, the probability that both choices will be defective machines is 0.1225
Answer:
think its x=3 hope it helps
Answer:
16
Step-by-step explanation:
Ⓗⓘ ⓣⓗⓔⓡⓔ
Well, 4*4 is equal to 4+4+4+4 which is also 16.
(っ◔◡◔)っ ♥ Hope this helped! Have a great day! :) ♥
Please, please give brainliest, it would be greatly appreciated, I only need one more before I advance, thanks!
Answer:
what does con sum mean they are the last two words in your question
Step-by-step explanation:
