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2 years ago

Please help me solve this !:) Explain your answer I will give braisnlt .

Mathematics

1 answer:

vovangra [49]2 years ago

7 0

Answer:

B & D

Step-by-step explanation:

both B and D are non linear because they're not lines

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The question is: type your equation for the following pattern

Nana76 [90]

Answer:

$\large\boxed{a(n)=16\left(\dfrac{1}{2}\right)^{n-1}}$

Step-by-step explanation:

$a(1)=16\\\\a(2)=16:2=8\\\\a(3)=8:2=4\\\\a(4)=4:2=2\\\\a(5)=2:2=1\\\\a(n)=a_{n-1}:2=\dfrac{1}{2}a_{n-1}$

This is a geometric series with the common ratio $r=\dfrac{1}{2}$ and the first term $a_1=16$ .

An explicit formula of the n-th term of a geometric sequence:

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Substitute:

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2 years ago

(05.01 MC) In triangle JKL, tan(b°) = three fourths and cos(b°) =four fifths. If triangle JKL is dilated by a scale factor of on

REY [17]

Answer:

$sin(b^\circ) = \dfrac{3}{5}$

Step-by-step explanation:

We are given a $\triangle JKL$ where $\angle K = 90^\circ$

$tan(b^\circ) = \dfrac{3}{4}\\cos(b^\circ) = \dfrac{4}{5}$

As per trigonometric rules,

$tan(\theta) = \dfrac{Perpendicular}{Base}$

$cos(\theta) = \dfrac{Base}{Hypotenuse}$

Comparing the given value of tangent and cosine:

Perpendicular = 3 units

Base = 4 units

Hypotenuse = 5 units

Also, we know that:

$sin(\theta) = \dfrac{Perpendicular}{Hypotenuse}$

$\Rightarrow sin(b^\circ) = \dfrac{3}{5}$

Now, it is given that the triangle is dilated by a scale factor of $\frac{1}{2}$ .

i.e. all the sides will become half of its initial values.

New Perpendicular = 1.5 units

New Base = 2 units

New Hypotenuse = 2.5 units

Using the formula for sine:

$sin(\theta) = \dfrac{Perpendicular}{Hypotenuse}$

$\Rightarrow sin(b^\circ)= \dfrac{1.5}{2.5}\\\Rightarrow sin(b^\circ)= \dfrac{15}{25}\\\Rightarrow sin(b^\circ)=\dfrac{3}{5}$

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3 years ago

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Answer:

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Multiply and divide first, making the equation 8811-17-1. Now subtract. This leaves 8793

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