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3 years ago

If you know why i got the point wrong for A and B please let me know right now i need it.

Mathematics

1 answer:

Inessa [10]3 years ago

6 0

Answer:

a.(-1,8), (2,9) b. (2,0) (3,5)

Step-by-step explanation:

for (-4, 7) slope is $\frac{1}{3}$

slope is m=rise /run =rise 1/run3 so to go to the next point

from (-4,7)

rise 1 so now you are at (-4,8) and run 3 and you are at (-1,8)

from (-1,8)

rise 1 to (-1, 9) and run 3 to (2,9)

(1,-5) slope is $\frac{5}{1}$

from (1,-5) rise 5 to (1,0) and run 1 to (2,0)

from (2,0) rise 5 to (2,5) and run 1 to (3,5)

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Read 2 more answers

F $1,000 is deposited in a certain bank account and remains in the account along with any accumulated interest, the dollar amoun

Whitepunk [10]

Answer:

(1) The annual interest rate is 10%, that is greater than 8%

(2) The annual interest is bigger than 22.47% and that is greater than 8%

Step-by-step explanation:

We have the equation:

$I=1,000((1+\frac{r}{100} )^{n} -1)$

Where I is the earns in interest, n is the number of years and r is the annual interest rate.

For the first case, we can replace I by $210 and n by 2 as:

$210=1,000((1+\frac{r}{100} )^{2} -1)$

Solving for r, we get:

$\frac{210}{1,000} = (1+\frac{r}{100})^{2} -1$

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$1.21 = (1+\frac{r}{100})^{2}$

$\sqrt{1.21} = 1 + \frac{r}{100}$

$\sqrt{1.21} - 1 = \frac{r}{100}$

$(\sqrt{1.21} - 1)100=r$

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So, for the first case, the interest rate paid by the bank is 10% and it is greater than 8%

For the second case, we need to take the equation and solve for r as:

$(1+\frac{r}{100} )^{2} >1.5$

$1+\frac{r}{100} > \sqrt{1.5}$

$\frac{r}{100} > \sqrt{1.5}-1$

$r > (\sqrt{1.5}-1)*100$

$r > 22.47$

So, for the second case the rate need to be bigger than 22.47% and that is bigger than 8%

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