Since we are given that the relationship between x and y
is linear. Therefore this means that the given equation takes the form of:
y = m x + b
where,
b is the y intercept of the equation
m is the slope of the equation
However we should take note that the slope m is directly
proportional to the coefficient of correlation. Since our coefficient of
correlation is negative, this only means that the value of y is decreasing with
increasing x, hence plot of y and x is descending with increasing x.
Furthermore, this also tells that for every 1 unit increase of x, there is a
0.75 units decrease of y.
So I think you should set up an equation like this: 14.95x+16.88y=131.18 , x+y=8
so x=8-y, plug this into the original equation:
14.95(8-y)+16.88y=131.18
Evaluate: 119.60-14.95y+16.88y=131.18
Combine like terms: 119.60+1.93y=131.18
Subtract 119.60 from both sides. You get: 1.93y=11.58
Divide both sides by 1.93. You get y=6
Plug into second equation: x+y=8 ---> x+6=8 and solve for x. x=2
Christine bought 2 video games and 6 CDs. 14.95(2)+16.88(6)=131.18
Answer:
No
Step-by-step explanation:
The upper Quartile is also known as the third quartile. And the greatest value is at the far right of the plot I placed an image below
Answer:
Step-by-step explanation:
H0 : μ = 46300
H1 : μ > 46300
α = 0.05
df = n - 1 = 45 - 1 = 44
Critical value for a one tailed t-test(since population standard deviation is not given).
Tcritical = 1.30
The test statistic :(xbar - μ) ÷ (s/sqrt(n))
The test statistic, t= (47800-46300) ÷ (5600√45)
t = 1500
t = 1500 / 834.79871
t = 1.797
The decision region :
Reject H0: if t value > critical value
1. 797 > 1.30
Tvalue > critical value ; We reject H0
Hence, there is sufficient evidence to conclude that cost has increased.
