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xeze [42]
3 years ago
15

In a popular online role playing game, players can create detailed designs for their character's "costumes," or appearance. Aaro

n sets up a website where players can buy and sell these costumes online. Information about the number of people who visited the website and the number of costumes purchased in a single day is listed below.
41 visitors purchased no costume.
78 visitors purchased exactly one costume.
10 visitors purchased more than one costume.
If next week, he is expecting 2000 visitors, about how many would you expect to buy more than one costume? Round your answer to the nearest whole number.
Mathematics
1 answer:
Stells [14]3 years ago
3 0

Answer:

115

Step-by-step explanation:

41 no costume, 78 exactly one costume, 10 more than one costume.

41+78+\color{steelblue}{10}=

41+78+10=

\,\,\color{indianred}{129}

129

There were a toal of 129 visitors. 10 purchased more than one costume.

Probability the next customer will purchase more than one costume:

\frac{\color{steelblue}{10}}{\color{indianred}{129}}\phantom{=}

129

10

​  

=

\,\,

Out of 2000 new trials, we would expect more than one costume to be selected:

\color{purple}{2000}\times\frac{\color{steelblue}{\color{steelblue}{10}}}{\color{indianred}{\color{indianred}{129}}}=

2000×  

129

10

​  

=

\,\,155.038759...

155.038759...

\approx

≈

\,\,155

155

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