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Alexxandr [17]
3 years ago
15

Plzzz help me PLZZ IM GIVING 10 POINTS TO THE FIRST PERSON

Mathematics
1 answer:
joja [24]3 years ago
6 0

Step-by-step explanation:

where is d question , the ans is minus 3

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Use the compound interest formula, . If $10,000 is invested at 2 percent quarterly for 5 years, what is the amount at the end of
Sonbull [250]
<span>The answer to this question is either 6.16778% or 6%

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4 0
3 years ago
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Verify whether the indicated numbers are zeroes of their corresponding polynomials.
Mashcka [7]

Answer:

  • No, incorrect

Step-by-step explanation:

<u>Given</u>

  • Q(s) = -4s^3 + 7s^2 - 24;
  • s = -4 and 1

<u>Verifying zeroes</u>

Q(-4) =

  • -4(-4)^3 + 7(-4)^2 - 24 =
  • 256 + 112 - 24 =
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  • Incorrect as 344 ≠ 0

Q(1) =

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8 0
3 years ago
PLEASE NEED ANSWER FAST
ahrayia [7]

c or d for sure hope this helps

5 0
2 years ago
State the horizontal asymptote of the rational function. f(x) = quantity x squared plus three x minus two divided by quantity x
omeli [17]

f(x)=\dfrac{x^2+3x-2}{x-2}\\ D_f=\mathbb{R}\setminus\{2\}\\\\ \displaystyle \lim_{x\to \infty}\dfrac{x^2+3x-2}{x-2}=\lim_{x\to \infty}\dfrac{x\left(x+3-\dfrac{2}{x}\right)}{x\left(1-\dfrac{2}{x}\right)}=\lim_{x\to \infty}\dfrac{x+3-\dfrac{2}{x}}{1-\dfrac{2}{x}}=\dfrac{\infty}{1}=\infty\\ \lim_{x\to -\infty}\dfrac{x^2+3x-2}{x-2}=\lim_{x\to -\infty}\dfrac{x\left(x+3-\dfrac{2}{x}\right)}{x\left(1-\dfrac{2}{x}\right)}=\lim_{x\to -\infty}\dfrac{x+3-\dfrac{2}{x}}{1-\dfrac{2}{x}}=\dfrac{-\infty}{1}=-\infty

The limits are not numbers, so the asymptote doesn't exist.

8 0
3 years ago
The number 312 lies between what two perfect squares?
Len [333]
Answer:
B) 216 and 330
or
C) 216 and 343

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7 0
3 years ago
Read 2 more answers
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