What are factors of the expression (y-2)(x+3)

Adriano wants to get a new cell phone plan. Company A: $80 for a new phone in the monthly fee of $45 a month. Company B: she can

Degger [83]

Answer: it will take 2 months.

Step-by-step explanation:

Let x represent the number of months it will take for the total cost for both companies to be equal.

Company A: $80 for a new phone and the monthly fee of $45 a month. This means that the total amount that Company A charges for x months would be

80 + 45x

Company B: she can keep her all sound and pay $85 a month. This means that the total amount that Company B charges for x months would be

85x

For the total cost for both companies to be equal, the number of months would be

80 + 45x = 85x

85x - 45x = 80

40x = 80

x = 80/40 = 2

3 0

3 years ago

Simplified form of the expression (x^3+3x^2+6)-(9x^2-5x+7)

JulijaS [17]

$(x^3 + 3x^2 + 6) - (9x^2 - 5x + 7)\\\\x^3 + 3x^2 + 6 - 9x^2 + 5x - 7\\x^3 - 6x^2 + 5x -1$

8 0

3 years ago

PLEASE CHECK PLS HELP AND FIND ANSWER

kari74 [83]

Here:

PFA for the answers. The numbering might confuse you. It goes from the 1 to the last marked question in ascending order. Hope it helps you. ~BYE

6 0

3 years ago

John has a rectangular-shaped field whose length is 62.5 yards and width is 45.3 yards. The area of the field is ________ square

xxMikexx [17]

2831.25 is the area and 215.6 is the perimeter

3 0

3 years ago

1) A family consisting of three persons—A, B, and C—goes to a medical clinic that always has a doctor at each of stations 1, 2,

crimeas [40]

Answer:

Step-by-step explanation:

Let us record the station number 1, 2 or 3 for each family member A, B or C.

I am attaching a table containing total outcomes. Outcomes are presented along rows while the assigned station to each member is written along columns. For ease of understanding, 1 3 2 in the table should be interpreted as family member A being assigned to station 1, member B to station 3 and member C to station number 2, respectively.

From table it is clear that the total outcomes possible are 27.

We know that, probability can be defined as,

$PROBABITILY = \frac{NUMBER\;OF\;DESIRED\;OUTCOMES}{TOTAL\;NUMBER\;OF\;OUTCOMES}$

a) All Members Assigned to the Same Station.

Cases for all members being assigned to same station are as follows:

[1 1 1], [2 2 2], [3 3 3] (outcome number 1, 14 and 27 in the table).

Therefore,

$PROBABILITY\;(Case\;a) = \frac{3}{27}\\\\PROBABILITY\;(Case\;a) = 0.111$

b) At Most Two Members Assigned to the Same Station.

It means that maximum of 2 members can have the same station. Cases for this situation are as follows:

[1 1 2], [1 1 3], [1 2 1], [1 2 2], [1 3 1], [1 3 3], [2 1 1], [2 1 2], [2 2 1], [2 2 3], [2 3 2],

[2 3 3], [3 1 1], [3 1 3], [3 2 2], [3 2 3], [3 3 1], [3 3 2]

(outcome number 2, 3, 4, 5, 7, 9, 10, 11, 13, 15, 17, 18, 19, 21, 23, 24, 25 and 26 in the table).

Therefore,

$PROBABILITY\;(Case\;b) = \frac{18}{27}\\\\PROBABILITY\;(Case\;b) = 0.666$

c) All Members Assigned to a Different Station.

For this scenario, we have the following results:

[1 2 3], [1 3 2], [2 1 3], [2 3 1], [3 1 2], [3 2 1] (outcome number 6, 8, 12, 16, 20 and 22 in the table).

Therefore,

$PROBABILITY\;(Case\;c) = \frac{6}{27}\\\\PROBABILITY\;(Case\;c) = 0.222$

3 0

3 years ago