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3 years ago

I WILL GIVE BRAINLIEST TO WHOEVER IS CORRECT.

Mathematics

1 answer:

Dovator [93]3 years ago

5 0

The answer is A. 3 2/15

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SOMEONE HELPPPPP I DONT UNDERSTAND

tatiyna

Step-by-step explanation:

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2 years ago

Can someone help me solve 3x-4y>-4

ahrayia [7]

What do you mean by solve?
Put in slope-intercept form would be: y<(3/4)x+1

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3 years ago

This is just in case you need help.....

Marta_Voda [28]

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3 years ago

The pharmacist uses 67mg, 100g and 0.6 kg of drug to compound 3 separate precription. how much total drug did the pharmacist use

FromTheMoon [43]

Answer: 700.067 g

Step-by-step explanation:

Given : The pharmacist uses 67mg, 100g and 0.6 kg of drug to compound 3 separate prescription.

We know that 1 gram= 1000 milligram

and 1 kilogram = 1000 grams

Then, By UNITARY METHOD, $\text{1 mg}=\dfrac{1}{1000}\text{ gram}$

Now, We convert each amount of drug into grams as ,

$67\ mg=67\times\dfrac{1}{1000}\ g\\\\=0.067\text{ g}$

AND

$0.6\ kg=0.6\times100=60\text{ g}$

Now, the total drug used by Pharmacist (in grams) = $0.067+100+600=700.067\ g$

Hence, Pharmacist used 700.067 g of total drug.

8 0

3 years ago

Suppose that a large mixing tank initially holds 100 gallons of water in which 50 pounds of salt have been dissolved. Another br

Serggg [28]

Answer:

dA/dt = 12 - 2A/(100 + t)

Step-by-step explanation:

The differential equation of this problem is;

dA/dt = R_in - R_out

Where;

R_in is the rate at which salt enters

R_out is the rate at which salt exits

R_in = (concentration of salt in inflow) × (input rate of brine)

We are given;

Concentration of salt in inflow = 4 lb/gal

Input rate of brine = 3 gal/min

Thus;

R_in = 4 × 3 = 12 lb/min

Due to the fact that solution is pumped out at a slower rate, thus it is accumulating at the rate of (3 - 2)gal/min = 1 gal/min

So, after t minutes, there will be (100 + t) gallons in the tank

Therefore;

R_out = (concentration of salt in outflow) × (output rate of brine)

R_out = [A(t)/(100 + t)]lb/gal × 2 gal/min

R_out = 2A(t)/(100 + t) lb/min

So, we substitute the values of R_in and R_out into the Differential equation to get;

dA/dt = 12 - 2A(t)/(100 + t)

Since we are to use A foe A(t), thus the Differential equation is now;

dA/dt = 12 - 2A/(100 + t)

5 0

3 years ago