Answer:
3 million barrels
Step-by-step explanation:
Total crude oil=60 million barrels
gasoline 34% diesel 29% total crude oil -60 million barrel · =0.34 times 60
Diesel=20,400,000 and gasoline=17,400,000
Quantity of gasoline = 34% of total crude oil
=0.34 times 60 =20.4
Quantity of diesel = 29% of total crude oil
=0.29 times 60 { million barrels}
Clearly, Quantity of gasoline is more than Quantity of diesel
difference = Quantity of gasoline-Quantity of diesel
20.4 -17.4 milion barrels
Therefore,
The production of gasoline is 3 million barrels more than diesel last year.
Answer:
3·(x - 14) + 1 = - 4·x + 5
3·x - 42 + 1 = - 4·x + 5
3·x - 41 = - 4·x + 5
7·x - 41 = 5
7·x = 46
x = 46/7
Answer:
y = x + 3
Step-by-step explanation:
The equation of a line is y=mx + b, where m is the slope and b is the y-intercept.
In this case, the slope of the line is 1, and the y-intercept (the point where the line crosses the vertical axis) is 3. So you just need to plug in the 3 in place of b.
y = mx + b
m = 1
b = 3
y = x + 3
Just like at any other time, to add/subtract fractions you need a common denominator.
14)
1/(x^2+2x)+(x-1)/x=1 so we need a common denominator of x(x^2+2x)
[1(x)]/(x(x^2+2x))+[(x-1)(x^2+2x)]/(x(x^2+2x))=[1(x(x^2+2x))]/(x(x^2+2x))
now if you multiply both sides of the equation by x(x^2+2x) you are left with:
x+(x-1)(x^2+2x)=x(x^2+2x)
x+x^3+2x^2-x^2-2x=x^3+2x^2
x^3+x^2-x=x^3-2x^2
x^2-x=-2x^2
3x^2-x=0
x(3x-1)=0, x=0 is an extraneous solution as division by zero is undefined. So the only real solution is:
x=1/3
...
16)
(r+5)/(r^2-2r)-1=1/(r^2-2r) the common denominator we need r^2-2r so
[r+5-1(r^2-2r)]/(r^2-2r)=1/(r^2-2r), multiplying both sides by r^2-2r yields:
r+5-r^2+2r=1
-r^2+3r+5=1
-r^2+3r+4=0
r^2-3r-4=0
(r-4)(r+1)=0, r^2-2r cannot equal zero, r(r-2)=0, r cannot equal 0 or 2...
r=-1 or 4
