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Neporo4naja [7]
3 years ago
12

Need help quick Picture provided proof problem

Mathematics
1 answer:
Doss [256]3 years ago
7 0
Uhhh i dont know bsjsiw
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Question 4 of 17
Vlada [557]

Answer:

I think it is A OR D

4 0
3 years ago
Help me please and thank you
Fittoniya [83]

There are 650 toothpicks in a regular sized box.

That is the volume of the box = 650 toothpicks

Jumbo box is made by doubling all the dimensions.

We know volume = length * width * height = L*W*H

We double all the dimensions for Jumbo box

L becomes 2L

W become 2W

H becomes 2H

Volume of Jumbo box = 2L * 2W * 2H = 8*L*W*H

Volume of jumbo box = 8 * volume of small box

= 8 * 650= 5200

The Jumbo box holds 5200 toothpicks .

7 0
4 years ago
A data mining routine has been applied to a transaction dataset and has classified 88 records as fraudulent (30 correctly so) an
chubhunter [2.5K]

Answer:

The classification matrix is attached below

Part a

The classification error rate for the records those are truly fraudulent is 65.91%.

Part b

The classification error rate for records that are truly non-fraudulent is 96.64%

Step-by-step explanation:

The classification matrix is obtained as shown below:

The transaction dataset has 30 fraudulent correctly classified records out of 88 records, that is, 30 records are correctly predicted given that an instance is negative.

Also, there would be 88 - 30 = 58 non-fraudulent incorrectly classified records, that is, 58 records are incorrectly predicted given that an instance is positive.

The transaction dataset has 920 non-fraudulent correctly classified records out of 952 records, that is, 920 records are correctly predicted given that an instance is positive.

Also, there would be 952 - 920 = 32 fraudulent incorrectly classified records, that is, 32 records incorrectly predicted given that an instance is negative.

That is,

                                                                            Predicted value

                           Active value                 Fraudulent       Non-fraudulent

                              Fraudlent                         30                       58

                          non-fraudulent                   32                     920

The classification matrix is obtained by using the information related to the transaction data, which is classified into fraudulent records and non-fraudulent records.

The error rate is obtained as shown below:

The error rate is obtained by taking the ratio of \left( {b + c} \right)(b+c) and the total number of records.

The classification matrix is, shown above

The total number of records is, 30 + 58 + 32 + 920 = 1,040

The error rate is,

\begin{array}{c}\\{\rm{Error}}\,{\rm{rate}} = \frac{{b + c}}{{{\rm{Total}}}}\\\\ = \frac{{58 + 32}}{{1,040}}\\\\ = \frac{{90}}{{1,040}}\\\\ = 0.0865\\\end{array}  

The percentage is 0.0865 \times 100 = 8.65

(a)

The classification error rate for the records those are truly fraudulent is obtained by taking the rate ratio of b and \left( {a + b} \right)(a+b) .

The classification error rate for the records those are truly fraudulent is obtained as shown below:

The classification matrix is, shown above and in the attachment

The error rate for truly fraudulent is,

\begin{array}{c}\\FP = \frac{b}{{a + b}}\\\\ = \frac{{58}}{{30 + 58}}\\\\ = \frac{{58}}{{88}}\\\\ = 0.6591\\\end{array}  

The percentage is, 0.6591 \times 100 = 65.91

(b)

The classification error rate for records that are truly non-fraudulent is obtained by taking the ratio of d and \left( {c + d} \right)(c+d) .

The classification error rate for records that are truly non-fraudulent is obtained as shown below:

The classification matrix is, shown in the attachment

The error rate for truly non-fraudulent is,

\begin{array}{c}\\TP = \frac{d}{{c + d}}\\\\ = \frac{{920}}{{32 + 920}}\\\\ = \frac{{920}}{{952}}\\\\ = 0.9664\\\end{array}

The percentage is, 0.9664 \times 100 = 96.64

8 0
3 years ago
the sum of the first four terms of an A.p is 62.if the difference between 4 terms and 2nd terms is 14. find the first term and c
Oksana_A [137]

Answer:

-2 -4 -6 -8

Step-by-step explanation:

I got the answer off of khan academy

3 0
3 years ago
What value of w solves the equation?<br><br> w^-3 = 1/64<br><br> w=___
Minchanka [31]
w^{-3}= \frac{1}{64} \\ \frac{1}{w^3} = \frac{1}{64} \\ w^3=64 \\ w= \sqrt[3]{64}\\ w= \sqrt[3]{4^3}  \\ w=4
8 0
3 years ago
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