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meriva
2 years ago
14

Larry and 3 friends went to a basketball game. They

Mathematics
1 answer:
Tju [1.3M]2 years ago
3 0
5x3= 15
The tickets were $15 in total
28-15= 13
13:3= 4’3
Each bag of candy was $4’3
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defon

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Let A be the event that the disease is present in a particular person

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The problem asks to find P(A|B), where

P(A|B) = P(B|A)*P(A) / P(B) = (P(B|A)*P(A)) / (P(B|A)*P(A) + P(B|~A)*P(~A))

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P(B|~A) = 0.02 (probability a person tests positive given they do not have the disease)

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P(A|B) = (0.98*0.009) / (0.98*0.009 + 0.02*0.991)

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2 years ago
Pls answer
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Answer:

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Step-by-step explanation:

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3 years ago
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