Question

The length of a rectangle is 3ft less than double the width, and the area of the rectangle is 14ft^2 find the dimensions of rectangle.

Answer 1

Answer: $4\times 3.5\ ft^2$

Step-by-step explanation:

Given

area of the rectangle is $A=14\ ft^2$

Suppose width is given by w

So, length is $l=2w-3$

The area of a rectangle is $A=l\times w$

putting values

$\Rightarrow A=(2w-3)w\\\Rightarrow 14=2w^2-3w\\\Rightarrow 2w^2-3w-14=0\\\Rightarrow 2w^2-7w+4w-14=0\\\Rightarrow w(2w-7)+2(2w-7)=0\\\Rightarrow (2w-7)(w+2)=0\\\\\Rightarrow w=\dfrac{7}{2}\ ft$

length is $l=4\ ft$