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solmaris [256]
2 years ago
12

Please help me answer this

Mathematics
1 answer:
xenn [34]2 years ago
3 0

9514 1404 393

Answer:

  B, C, D

Step-by-step explanation:

You can solve for x, or you can try x=3.5 to see if that makes the equation true. Here, we decided to solve for x.

A. x =(8×3 -3)/7 = 3

B. x = 15 -11.5 = 3.5

C. x = (34 -6)/8 = 3.5

D. x = 15.5 -12 = 3.5

E. x = 20 -15.5 = 4.5

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At a bargain store, Tanya bought 4 items that each cost the same amount. Tony bought 5 items that each cost the same amount, but
Alex_Xolod [135]

If x is the amount that Tanya paid for each item, then Tony's items would be x-2.25. So:

3x=4(x-2.25)

3x=4x-9

x=9

x-2.25=6.75

Tanya spent $9 on each item; Tony spent $6.75 on each of his items. ☺☺☺☺

6 0
3 years ago
3 determine the highest real root of f (x) = x3− 6x2 + 11x − 6.1: (a) graphically. (b) using the newton-raphson method (three it
Juliette [100K]

(a) See the first attachment for a graph. This graphing calculator displays roots to 3 decimal places. (The third attachment shows a different graphing calculator and 10 significant digits.)

(b) In the table of the first attachment, the column headed by g(x) gives iterations of Newton's Method. (For Newton's method, it is convenient to let the calculator's derivative function compute the derivative f'(x) of the function f(x). We have defined g(x) = x - f(x)/f'(x).) The result of the 3rd iteration is ...

... x ≈ 3.0473167

(c) The function h(x₁, x₂) computes iterations using the secant method. The results for three iterations of that method are shown below the table in the attachment. The result of the 3rd iteration is ...

... x ≈ 3.2291234

(d) The function h(x, x+0.01) computes the modified secant method as required by the problem statement. The result of the 3rd iteration is ...

... x ≈ 3.0477377

(e) Using <em>Mathematica</em>, the roots are found to be as shown in the second attachment. The highest root is about ...

... x ≈ 3.0466805180

_____

<em>Comment on these methods</em>

Newton's method can have convergence problems if the starting point is not sufficiently close to the root. A graphing calculator that gives a 3-digit approximation (or better) can help avoid this issue. For the calculator used here, the output of "g(x)" is computed even as the input is typed, so one can simply copy the function output to the input to get a 12-significant digit approximation of the root as fast as you can type it.

The "modified" secant method is a variation of the secant method that does not require two values of the function to start with. Instead, it uses a value of x that is "close" to the one given. For our purpose here, we can use the same h(x1, x2) for both methods, with a different x2 for the modified method.

We have defined h(x1, x2) = x1 - f(x1)(f(x1)-f(x2))/(x1 -x2).

6 0
2 years ago
A 50-foot flagpole is at the entrance of a building that is 300 feet tall. If the length of the flagpole's shadow is 30 feet at
Soloha48 [4]

The equation you can use to solve the problem is;

50/30 = 300/x

Next Cross Multiply

50x = 9000

x = 9000/50

x = 180

The building's shadow is 180 feet tall

7 0
2 years ago
Whats the equation of a line perpendicular to y= 0.25x-7 and passes through (-6,8)
-Dominant- [34]
y - 8 = 4(x + 6)
The slope perpendicular to 1/4 or .25 is 4.
Then you would use point slope form to write the equation.
Then you could simiplify the equation to y=4x+32.
8 0
3 years ago
Drag steps in the given order to evaluate this expression. <br><br> (4)(−3)−5−3(−6)
never [62]

Answer:

1

Step-by-step explanation:

using PEDMAS(parentheses, exponents, division, multiply, addition, subtraction) to solve the problem

First we multiply (4)(-3)

(4)(−3)−5−3(−6)

Then multiply -3(-6)

(-12)-5-3(-6)

=-12-5+18

subtract 12-5

-12-5+18

=-17+18

Adding -17+18 gives us 1.

Therefore,  (4)(−3)−5−3(−6) is 1.

3 0
3 years ago
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