Here’s a pic of my work, it shows that the numbers 2,7,0 repeat.
Hope this helps!! :)
Question # 1
Answer:

Step-by-step explanation:
Given the expression

∵ 
∵ 








Therefore,

Question # 2
Answer:

Step-by-step explanation:
Given

∵ 
∵ 










Therefore,

(fg)(x)=f(g(x))=4(g(x))²-5=4(x+3)²-5=4x²+24x+31
There are 256 cups of water needed. I hope this helped.
Answer:
y=mx+c
Step-by-step explanation:
A linear equation means the equation of straight line.
The formula for equation of straight line in slope intercept form is y=mx+c
where, m is the slope of line and c is the y intercept
The formula for equation of straight line in double intercept form is x/a+y/b=1
The formula for equation of straight line in normal form is xcos α + y cos α=p
There are more formulas bur assuming you are asking for the general representation of the straight-line equation, it is y=mx+c.