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kicyunya [14]
3 years ago
14

You have just secured a job at a web development company. You get paid $19.50 an hour and work

Mathematics
1 answer:
Tpy6a [65]3 years ago
8 0

39,000 PER YEAR FOR THIS

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What is the slope of a line that goes through (0,0) amd (5,-1)
statuscvo [17]
Slope of line is -1/5 !!!!!!!!!!!
3 0
3 years ago
Read 2 more answers
Make a ten or hundred to add mentally 198+132
Veseljchak [2.6K]
2000. Because if you add the 2  it will make 1200, 2+8 is 10 so you carry the 1, and 3+9 is 12 then you add the 1 you got from 10 and you have 13. then you add 1+1 and get 2 and add the 1 you got from 13 so there you have it.
6 0
3 years ago
Find the discriminant, and determine the number of real solutions. then solve x^2 +8x+20=0
vodomira [7]

Answer:

Part 1) The quadratic equation has zero real solutions

Part 2) The solutions are

x_1=-4+2i   and x_2=-4-2i

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form ax^{2} +bx+c=0 is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

x^{2}+8x+20=0  

so

a=1\\b=8\\c=20

The discriminant is equal to

D=(b^{2}-4ac)

If D=0 -----> the quadratic equation has only one real solution

If D>0 -----> the quadratic equation has two real solutions

If D<0 -----> the quadratic equation has two complex solutions

<em>Find the value of D</em>

D=8^{2}-4(1)(20)=-16 -----> the quadratic equation has two complex solutions

<em>Find out the solutions</em>

substitute the values of a,b and c in the formula

x=\frac{-8(+/-)\sqrt{8^{2}-4(1)(20)}} {2(1)}

x=\frac{-8(+/-)\sqrt{-16}} {2}

Remember that

i=\sqrt{-1}

x=\frac{-8(+/-)4i} {2}

x_1=\frac{-8(+)4i} {2}=-4+2i

x_2=\frac{-8(-)4i} {2}=-4-2i

8 0
4 years ago
Can 12 cm 12 cm and 28 cm form a triangle
erastova [34]
Using the Theorem of Pythagoras (a² + b² = c²)

Put in the values:

12² + 12² = 28²
Is it correct? (solve)

Nope! Because 12² + 12² = 288, and the square root of 288 is about 17, not 28.

The answer is no, 12cm, 12cm, 28cm cannot form a triangle.

Hopefully this helps! If you have any more questions or don't understand, feel free to DM me, and I'll get back to you ASAP! :)
3 0
3 years ago
Prove: If C⊂A and D⊂B then D−A⊂B−C
nalin [4]
Let x\in D\setminus A, so that x\in D but x\not\in A. Since D\subset B, it follows that x\in B, and since C\subset A, it follows that x\not\in C, which means x\in B\setminus C.
3 0
3 years ago
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