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2 years ago

Solve the linear equation for x. –4.8(6.3x – 4.18) = –58.56 x =

Mathematics

2 answers:

liq [111]2 years ago

7 0

Answer:

X=2.6

Step-by-step explanation:

anyanavicka [17]2 years ago

5 0

Answer:

x=2.6

Step-by-step explanation:

1. 6.3x−4.18= $\frac{-58.56}{-4.8}$

2. 6.3x-4.18=12.2

3. 6.3x=12.2+4.18

4. 6.3x=16.38

5. x= $\frac{16.38}{6.3}$

6. x=2.6

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How do i solve this problem 1/15+1/6

Semenov [28]

Answer:

7/30

Step-by-step explanation:

1/6 = 1x5/6x5

= 5/30

1/15= = 1x2/1x15

=2/30

2/30 + 5/30 = 7/30

5 0

3 years ago

You have to make 1000 buttons.the diameter of the button is 9cm but you have to find it’s area.its $15/m squared and you have to

Semmy [17]

Answer:

$95.38

Step-by-step explanation:

step 1

Find the area of one button

The area is equal to

$A=\pi r^{2}$

we have

$r=9/2=4.5\ cm$ ---> the radius is half the diameter

Convert to meters

$r=4.5\ cm=4.5/100=0.045\ m$

assume

$\pi =3.14$

substitute

$A=(3.14)(0.045)^{2}\\A=0.0063585\ m^2$

step 2

Find the area of 1,00 buttons

Multiply by 1,000

$A=0.0063585(1,000)=6.3585\ m^2$

step 3

Find the cost

Multiply $15 per square meter by the total area of 1,000 buttons

$(15)6.3585=\$95.38$

3 0

3 years ago

Which point do the graphs of f and g have in common?

pickupchik [31]

The point that the graphs of f and g have in common are (1,0)

<h3>How to get the points?</h3>

The given functions are:

f(x) = log₂x

and

g(x) = log₁₀x

We know that logarithm of 1 is always zero.

This means that irrespective of the base, the y-values of both functions will be equal to 0 at x=1

Therefore the point the graphs of f and g have in common is (1,0).

Learn more about graph on:

brainly.com/question/19040584

#SPJ1

6 0

1 year ago

Work out the area of this trapezium

skelet666 [1.2K]

Step-by-step explanation:

Area = ½ × b × h

= ½ × (7.9 + 10.8) × 6.2

= ½ × 18.7 × 6.2

= ½ × 115.94

= 57.97 cm²

So, the area of that trapezium is 57.97 cm²

Hope it helpful and useful :)

6 0

2 years ago

PLEASE HELPP MEEEEE

pav-90 [236]

The smallest region that can be photographed is
5*7 = 35 square km
so we want to know how long it takes to zoom out to an area of
35 * 5 = 175 square km.

Notice that the length and width increase at the same rate, 2 km/sec, and they start out with a difference of two, so when the width has increased from 5 to x, the length will have increased from 7 to x+2. At the desired coverage area, then,
x(x+2) = 175
x^2 + 2x = 175
x^2 + 2x + 1 = 176 [completing the square]
(x+1)^2 = 176
x+1 = ±4√11
x = -1 ±4√11

Since a negative value for x is meaningless here, x must be
-1 + 4√11 = about 12.27 km
and the time it took to increast to that value was
(12.27 - 5) km / (2 km/sec) = about 3.63 seconds

6 0

3 years ago